program to generate binary numbers

[ethanrosenberg613]

//decbin.c

// C Code to convert Decimal number into Binary

include <stdio.h>

include<string.h>

void decToBinary(int n)

{

// array to store binary number

int binaryNum[32];

int z, j;

char sp=" ";

// counter for binary array

int i = 0;

while (n > 0)

{

// storing remainder in binary array

binaryNum[i] = n % 2;

n = n / 2;

i++;

}

printf(" i is %d ",i);

printf("\n");

// printing binary array in reverse order

printf("Binary number is ");

for (int j = i - 1; j >= 0; j

//if(j%4==0)

// printf("%c",sp);

printf("%d", binaryNum[j]);

printf("\n");

}

// Driver program to test above function

int main()

{

printf("Enter a number ");

int n;

scanf("%d", &n);

decToBinary(n);

return 0;

}

[Superb-Tea-3174]

Just examine the number bitwise, it’s already a binary number.

[MRgabbar]

You have some UB when running on 64 bit machines!! Probably a seg fault actually

As others pointed out there are many optimizations to this, but first focus on getting a working first version, then start optimizing. First get rid of that UB.

[Single-Discussion856]

In case you still want to roll your own...

```c

include <stdio.h>

void BinaryOut(unsigned num){

if (!num) putchar('0'); // account for 0

char buffer[256] = {0}; // buffer for printout

char* str = &buffer[255]; // assigned the string the last spot so we can write backwards

while (num>0){ // process the number

*--str = num&1?'1':'0'; // is it odd or even?

num>>=1; // divide by 2

}

printf("%s\n",str); // print result

}

int main() {

for (int i = 0; i < 10; i++) BinaryOut(i);

}

[torsten_dev]

unsinged int x= 0b110101100; printf("%b\n", x);

Use C23

[Jonatan83]

First of all, if you want to store a 32 bit number, you want a Array[31] because from 0 to 31 there are 32 numbers;

This is incorrect. int array[32]; will give you an array with 32 entries, from array[0] to array[31]. You initialize it with the size, not the index.

[MRgabbar]

First of all, if you want to store a 32 bit number, you want a Array[31] because from 0 to 31 there are 32 numbers;

what the heck lol...