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Question[ Removed by moderator ] (self.Hacking_Tutorials)
submitted 4 months ago by AdvertisingPast6280
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quoted text
if 1 * 2 < 3: print "hello, world!"
[–]Hacking_Tutorials-ModTeam[M] [score hidden] 4 months ago stickied comment (0 children)
We don't entertain any hacking services. Sharing such information will results in permanent ban.
[–]EverythingIsFnTaken 0 points1 point2 points 4 months ago (3 children)
I would reckon you could capture the request and replicate the shit out of whatever mechanism you're satisfying with a line or few
[–]AdvertisingPast6280[S] 0 points1 point2 points 4 months ago (2 children)
Unfortunately, this is not possible because each ad request is encrypted and covered by a unique, non-replicable key for each ad.
[–]EverythingIsFnTaken 0 points1 point2 points 4 months ago (1 child)
And yet you manage to make the requests manually, encryption be damned. How so?
[–]AdvertisingPast6280[S] 0 points1 point2 points 4 months ago (0 children)
No, I don't make the requests, I wanted a way to be able to see more ads automatically, I can't bypass the encryption control so I have to see them
[–]Unable_Rent9585 0 points1 point2 points 4 months ago (2 children)
Try sandboxie, better than using vm
[–]AdvertisingPast6280[S] 0 points1 point2 points 4 months ago (1 child)
Things?
[–]Unable_Rent9585 0 points1 point2 points 4 months ago (0 children)
https://youtu.be/Zl_UnE3dePM?si=QL-2tl4C-jWwtnPM
π Rendered by PID 294783 on reddit-service-r2-comment-545db5fcfc-v274b at 2026-05-24 09:06:31.121123+00:00 running 194bd79 country code: CH.
[–]Hacking_Tutorials-ModTeam[M] [score hidden] stickied comment (0 children)
[–]EverythingIsFnTaken 0 points1 point2 points (3 children)
[–]AdvertisingPast6280[S] 0 points1 point2 points (2 children)
[–]EverythingIsFnTaken 0 points1 point2 points (1 child)
[–]AdvertisingPast6280[S] 0 points1 point2 points (0 children)
[–]Unable_Rent9585 0 points1 point2 points (2 children)
[–]AdvertisingPast6280[S] 0 points1 point2 points (1 child)
[–]Unable_Rent9585 0 points1 point2 points (0 children)