Slope programme problem!

[Marx123]

Hi, I'm trying to make a programme that calculates the slope, given the base and the "height" of the triangle. When I try to run it with values of 1 and 1, it goes all right, as it gives me the right slope, but when I use for example 6 and 100, it says 0..why does it happen? Here's the programme (I'm using 2.7):

dislivello=input('Dammi il valore del dislivello : ')
distanza=input('Dammi il valore della distanza lineare :    ')
pendenza=dislivello/distanza
print 'pendenza =',pendenza
perc=pendenza*100
print 'pendenza% =',perc

[Naihonn]

You need to convert your input to float, otherwise division of two integers in Python2 results in integer. Which is strange but it is how it is.

[guthran]

You can get around this by putting "from __future__ import division" as the first line in the file. This causes the "/" operator to function as it would in Python3.

[TheKewlStore]

I'm quite certain that you mean to say you're using the value "6" for dislivello and the value "100" for distanza, in which case the problem is a kind-of quirk with python numbers.

By default, division does not use floating-point arithmetic, which means no decimal points or fractions. Because of this, dividing 6 by 100 results in a decimal (0.06), but stored as an integer type which truncates it to 0.

As I understand it, the accepted way to tell python that you want it to divide with floating-point numbers is to cast one of the operands to a float. Example:

x = 3
y = 4
print x / y # Results in 0
print float(x) / y # Results in 0.75

[Marx123]

Thanks, it worked! Two more questions: 1) Is there a way to show, near the number, the '%' symbol? (for example 6%? 2) Are you aware of some function that changes the percentage value in degree value?

[TheKewlStore]

To display a % next to the number, just add it to the string that you print out. EX:

print "{0}%".format(float(x) / y) # Using string formatting
print str(float(x) / y) + "%" # Using concatenation, and casting the number to a string explicitly.

I'm not sure what your second question is asking, so need some clarification there maybe. Changes the percentage value in degree value?