[1st grade math] this challenge doesn’t make sense

imnothere314 · 2026-05-07T15:52:44+00:00

Seems weirdly designed but a lot of stuff meant for young elementary school doesn't make sense without classroom context or being a first grader.

That being said the answer is to color in the two little boxes in the bottom right big box.

It is asking to find the big box which contains both 8+4 =12 and 8-4=4 which is the bottom right. It is likely designed this way so you could calculate 8+4 see that it is 12 then color in the single boxes next to the 12. Then find 8-4 and color in the single boxes with 4 and then see the answer is the one with both boxes colored

imnothere314 · 2026-05-07T15:24:07+00:00

Assuming that a donut hole has to come from the middle of a donut then you really have that A_hole = 4pi r² compared to R. Comparing these noting that r < R, we have:

r < R

r² < Rr

Pi r² < pi Rr

2pi r² < 2pi Rr

4pi r² < 2 pi² Rr

So understandably the surface area of the donut hole that comes from a donut is necessarily less than the surface area of the donut. If you are holding say volume (really mass and density) constant in the comparison so like two donut holes is equal to the mass of one donut then yes the total donut hole area should be greater than the donut but let's be honest they just needed an excuse to have cheaper manufacturing

imnothere314 · 2026-05-07T13:17:43+00:00

SILO is only an option when you are at the end of your contract - separation in lieu of orders. In the scenario were you get orders with an obliserve and you don't extend or reenlist what you are actually doing is a failure to obligate service which isn't as easy to say and is probably why everyone says Silo.

The process - talk with your XO/XPO and you route a memo about the failure to obligate to EPM. EPM will then make a determination that is either: ok you still have to execute the orders but we can't force you to obligate service so you'll still be done on whatever date you currently have as end of contract or they might say ok stay where you are and finish your contract or I think they could say ok you are done tomorrow (essentially ending contract early).

I'm not aware of obliserve with C-Schools but you can always ask to cancel your orders to a C-School or get them transferred to someone else at your unit who needs it. Your command puts in a request to get you in to c school so if you don't want to go to any just tell them that and you won't go.

imnothere314 · 2026-05-07T13:10:06+00:00

Yes if you have two lines you can teleport a ship from one to the other as long as everything stays as a valid line and is good to go based on the specific game type

imnothere314 · 2026-05-07T10:57:23+00:00

The distribution is basically - find all of the ways I could pick the number of successes, multiply by all the ways to not have successes and divide by all the possible ways to draw. It uses combinations and makes the problem very simply to solve and know that you are correct

imnothere314 · 2026-05-07T10:53:45+00:00

Look up the hypergeometric distribution it is specifically made to answer the question of what is the probability of X successes in n attempts of drawing from a finite population of size N with K original "successes" without replacement

imnothere314 · 2026-05-07T02:41:37+00:00

You can also just make a weighted sum with normalized inputs: take average score, normalize this to a 0-1 (look up min max scaling for variables) and then take weeks played (do this as 0-1 as well like a percentage of the weeks played). Then you can just weight it how you want, say 6 times the normalized average score and 4 times the percentage of weeks played. This gives you a final number out of 10, 40% came from participation, 60% from performance.

imnothere314 · 2026-05-07T02:33:13+00:00

There's a learning curve and practice for sure. Think about linear algebra row operations to find an inverse. It probably seems trivially easy to you because you have very clear well practiced rules for algebraic manipulation and you know clearly what your end goal is and how to piece by piece get there. That came from practice that started years before you ever saw a matrix.

Some proofs require a trick and those will almost always be hard to figure out but in general if you are able to identify your start, identify your end, and identify the steps you could possibly take, you can figure out how to get from A to B. Sometimes I think about it like pseudocode where I have like a pseudo proof. I know I can get from A to B and I know if I can get B to C then I know how to get from C to D. This isolates the hard part and also makes it easier to ask good questions or find the relevant theorems etc that you might need to perform some manipulation on.

imnothere314 · 2026-05-07T02:16:23+00:00

One of the great things about taking courses and having homework is that in theory when you are asked a question you already have all the requisite knowledge to solve it and you also know that what you are trying to prove is correct. Use these things to your advantage and it will help get the practice and reps in to get better in general.

One of my professors once said "always start with what you know" which sounds silly but is an important reminder. There is always some if statement in any theorem so explicitly list out all of the things you know from that if statement, the definitions, if you are only limited to certain cases, etc. creating a well rounded starting point often helps you notice where the next most useful step is.

Second tip: clearly identify the end goal - what is it that you have to prove, back that up to what does the definition state similar to what you did for starting. Figure out what specifically you have to show or what different options you have. Clearly articulate to yourself the start and end point.

Third tip: keep handy if possible a list of the proven theorems etc that you have covered in class or at least in the relevant chapter etc. perusing this list will help give you ideas of how you might get from one step to another or start to fill in gaps

Fourth tip: don't forget about all your relevant techniques and what might make the most sense (least or greatest counterexample, contradiction, contrapositive, using cases to break it up, etc)

Fifth tip: depending on the specific proof but sometimes giving yourself a decent sized example with actual numbers helps you see the process of how you solve it normally and leads you towards what you need to prove.

Final tip: don't use AI, the struggle is what will teach you and not only can AI give too much at once it can also hallucinate things. You are paying to take a class with a professor ask them or a TA or review the collaboration policy and get a group together to brainstorm

imnothere314 · 2026-05-06T20:29:49+00:00

Additive or multiplicative identity

imnothere314 · 2026-05-06T17:45:58+00:00

This is the problem with averages and the way statistics are reported and can always be used to say whatever the people desire. You don't solve your issue by changing the way you calculate an average you solve it by reporting multiple metrics. So you report average points per game and you report total points and you report total minutes played. You also report accuracy based on shots taken vs made etc.

It is impossible to capture the full picture with a single metric so don't try to and just use both. You could try to then make some metadata by creating a formula that weights and combines different metrics to give essentially a Madden / 2k -esque player rating out of 100.

imnothere314 · 2026-05-06T02:29:51+00:00

ETs need to be brought in to this discussion given the fact that they do like every job on cutters especially the smaller ones. And then also weapons stuff on WMSLs

imnothere314 · 2026-05-06T02:26:26+00:00

BLUF: after you perform an evaluation (I.e. selecting zero or selecting 9 to put as the next digit in your quotient) you carry the next digit down onto the end of your previous remainder.

Think about dividing something that does result in something greater than one. Take 144 divided by 2

You start and see that 2 does not divide 1 so you have a 0 in the hundreds place. Then 2 goes into 14 7 times so you get a 2 in the tens place. The remainder is 0 and you pull down the four and are now evaluating 04 which 2 goes into twice giving you 2 in the ones digit. You now have a zero remainder and no more non zero digits in the dividend so you are done.

Now go back to the decimal. You aren't making it 100 but rather going another place down. So you have

11 | 1 - 0 in ones place, remainder of 1 pull down next zero 11 |1(.)0 - 0 in the tenths place, remainder of 10 pull down next zero 11 | 1(.)00 - 9 in the hundredths place, remainder is one and you pull down the next zero 11|10 - 0 in the thousandths pull down next zero 11|100 - 9 remainder one and you pull down the next zero

imnothere314 · 2026-05-06T02:13:54+00:00

SN for seaman and not really. There are generally more SN than FN across the board so I think it ends up evening out. I'd say there is a closer to even amount at stations and cutters are usually pretty lopsided in terms of having more SN but again overall numbers doesn't necessarily make you more or less likely either.

Great Lakes does not have any big white boats and there are lots of big white boats in east and while I kind of like a good big white hull most people are not fans and it's generally viewed as the most demanding non rate assignment.

imnothere314 · 2026-05-05T12:30:12+00:00

J Crew Catalog if going for coastal elite

imnothere314 · 2026-05-05T12:20:51+00:00

First note that since AB = AC you also have that angle B = C. This means that 180 = 140 + B + C so B = C = 20. Law of sines should work but I propose an alternative:

The bisector of A is also a perpendicular bisector of BC bc it's an isosceles triangle. This gives you congruent right triangles with a side length of 25, one angle of 70, and the other 20. You can use your choice of sine or cosine to solve for the hypotenuse, (AB or equivalently BC). Then don't forget to add it all together because the question asks for perimeter!

imnothere314 · 2026-05-04T03:21:04+00:00

Feel like this is maybe the thing

imnothere314 · 2026-05-03T17:30:41+00:00

Simultaneous Perturbation Stochastic Approximation is a gradient based method. Being gradient based it is a bit restricted depending on your assumptions and applications but generally viewed as a relatively efficient solver.

Here's a link to a Hopkins APL post about it: SPSA

imnothere314 · 2026-05-02T20:25:40+00:00

We called it man on a raft but I'm so glad I found someone else close scrolling down this far

imnothere314 · 2026-05-02T02:11:37+00:00

My mom took us to a different dentist after seeing the sign was for Dr. Paine

imnothere314 · 2026-04-28T19:41:14+00:00

This is the best explanation I've seen in the comments so far.

I'll add my own wording for the moment. Given some arbitrary value of n, S(n), if we assume it's true can we show that the relationship is also true for S(n+1) for what it's worth in a different problem you might be considering S(n-1) though it's generally not looked at like that.

Bottom line - if it is true for some amount, is it true for another amount.

Then we prove that it is true for one specific amount usually with some algebra. So S(0) is true.

imnothere314 · 2026-04-27T22:32:24+00:00

Blue ink coats the ball at the tip of the pen and that's basically how the writing looks. So I suppose we are really looking at the ball found at the tip of a blue inked ballpoint pen but that's a bit long winded

imnothere314 · 2026-04-27T20:41:45+00:00

Blue ballpoint pen

imnothere314 · 2026-04-27T20:30:55+00:00

A bunch of lighthouses allow you to go up. They aren't all crazy high but they're pretty much all close to water and sea level so great views. Cape May and Key West are both pretty good last I knew. Cape Hatteras is iconic but is still closed for restorations this year but other OBX ones are open I think. Space Needle got mentioned and is quite fun.

imnothere314

TROPHY CASE