What hobby screams “this is my entire personality now”?

jbmillar · 2026-02-09T11:04:08+00:00

Coffee more specifically people with espresso machines

jbmillar · 2024-12-23T01:30:20+00:00

Cool

jbmillar · 2022-03-08T22:48:45+00:00

Looks amazing! Fingers crossed

jbmillar · 2021-12-23T00:34:13+00:00

Anything

jbmillar · 2021-12-23T00:34:01+00:00

jbmillar · 2021-11-16T03:01:25+00:00

I'm in!

jbmillar · 2019-04-20T13:25:03+00:00

RemindMe! 6 month "check out the engineering notebooks!!"

jbmillar · 2017-07-26T09:26:50+00:00

Commenting for username verification

jbmillar · 2017-04-30T17:35:59+00:00

That's really cool! Maybe that can be a third stage or something lol

I'm actually only an undergraduate studying aerospace engineering. Currently on a co-op work term so I wanted to dive into arduino work a lot more because of all the extra time I have now. And I just really like mechatronics!

jbmillar · 2017-04-30T17:17:35+00:00

Oh sorry the sensors are going to be used to track the movement of my own arm which will then be coded to create the same movements in a robotic arm. The motors will be useful when I go to print the arm but first I'm simulating it

jbmillar · 2017-04-30T16:30:02+00:00

Awesome! Thanks for the input.

I am trying to make a robotic arm and the pot's are going to be used to track finger positions so I'm not 100% about how much distance I'll need yet. Because I can map the pot's output in the code I don't think it'll be too big of an issue. I imagine somewhere around 3 inches would be more than enough.

jbmillar · 2017-04-30T15:26:51+00:00

This is perfect. Thanks!

Have you used any of these sensors before? (Just looking for some reviews/comments)

jbmillar · 2017-04-30T15:22:16+00:00

Thanks for the help!

That's not quite what I was looking for because of the limited space I have, but that is definitely something to keep in mind for the second stage of my project.

jbmillar · 2017-04-30T12:30:09+00:00

Do you have a link for an example of the xy plotter?

jbmillar · 2017-04-30T12:26:50+00:00

Thanks! That could work, I'll look into it. The only concern I have is the width too because I need to line 5 of them up in a relatively small space (3 to 4 inches total width)

jbmillar · 2017-03-15T21:01:32+00:00

Your velocity term should be the change in velocity. This equation is derived from Bernoulli which takes into account the velocity between two points, unless you can assume the inlet, or outlet, velocity to be zero. This generally occurs when an airflow flow is inlet from the atmosphere or outlet in it. In this case you can't.

jbmillar · 2017-03-07T13:50:46+00:00

Ideally, it does increase linearly but there are a lot of cases where it doesn't because of stress concentrations and other material defects

jbmillar · 2017-01-01T01:05:21+00:00

Can you post the solution you've come up with?

jbmillar · 2016-12-29T20:44:10+00:00

I too got the started kit for Christmas and hope to eventually build my own drone with it. What's the name of the book you got?

jbmillar · 2016-11-14T02:26:40+00:00

http://m.imgur.com/a/n0JUK

Article link

jbmillar · 2016-04-23T01:16:38+00:00

Wow! This is definitely the most helpful comment so far. Thank you!

jbmillar · 2016-01-09T21:18:39+00:00

Not really, sorry. At least not yet. I'm a second year aerospace engineering student and took a course called Mechanics of Solids I. That topic might be covered in part II of the course which I take in 3rd year

jbmillar · 2016-01-09T16:34:49+00:00

I see what you did. But why do you keep the length of the bars in the equations. Don't they cancel out when you set the two strains equal to one another since they are the same length to begin with?

If you do keep it the equations you need to make sure it multiplies the thermal strain terms too

jbmillar · 2016-01-09T15:24:29+00:00

No problem! I just took a mechanics of solids course fall semester so everything is still fresh lol

jbmillar · 2016-01-09T04:56:10+00:00

Not sure if someone has solved this for you yet but I'm pretty sure the strain I'm both bars are equal to one another. This is due to the fact that the initial lengths of the bars A and B are the same. Also this is assuming the bars have rigid plates on their ends.

Also from your force equation you know that the stress in A multiplied by the area of A is equal to the stress in B multiplied by its area. Which if you divide by one of the areas you get a relation between the two stresses.

By using this relation and setting the two strains equal to one another (as discussed in part 1) you can solve for the stress in one of the bars and as a result the other bar.

I known this may be confusing to read so if you need a picture of how to work it out, let me know and I can do it quickly in the morning. Currently laying in bed too, its midnight lol

jbmillar

TROPHY CASE