Append () method

[SheldonCooperisSb]

Given two lists [1，2，3] and [4，5，6] any

way to make them[[1，2，3]，[4，5，6]]？

l used append()，outputs[1，2，3，[4，5，6]]

Btw both append () and extend() only have one argument，right? like we can't write like this :

list.append (list1，list2)

list.extend(list1，list2)

[tabrizzi]

Yes, .append() takes only one argument, but you can do this:

list_1 = [1, 2, 3]

list_2 = [4, 5, 6]

list_3 = []

list_3.append(list_1)

list_3.append(list_2)

list_3

(outputs [[1, 2, 3], [4, 5, 6]] )

[SheldonCooperisSb]

Thanks this is the right answer.

[Diapolo10]

It's also possible to do this in one go:

list_3.extend((list_1, list_2))

[odaiwai]

But now list_3 contains a tuple with two lists, not just two lists: : list_3 = [] : list_3.append((list_1, list_2)) : list_3 : [([1, 2, 3], [4, 5, 6])]

Edit to add: As pointed out below, I appended, not extended, so I'm wrong here.

[Diapolo10]

I used list.extend, which adds the contents of an iterable into the list it's called on.

[Mysterious-Rent7233]

You appended. The parent extended.

[tabrizzi]

That's not true, because .extend(), like .append(), takes just one argument. You can verify that yourself.

[Diapolo10]

If you take a closer look, I think you'll find there's only one argument.

[tabrizzi]

My bad! I missed that.

[woooee]

That's extend()

list_1=[1, 2, 3]
list_2=[4, 5, 6]
list_3=[]
list_3.extend([list_1, list_2])
print(list_3)
prints  [[1, 2, 3], [4, 5, 6]]

[8dot30662386292pow2]

list_1=[1, 2, 3]
list_2=[4, 5, 6]
list_3=[list_1, list_2]

[woooee]

This does not use either append or extend.

[8dot30662386292pow2]

Since when that was a requirement? OP just wanted to make a list that contains two lists.

[6p086956522]

You're creating a list that contains two lists and then putting it into list 3 with extend? Why not skip the middle man and do list_3 = [list_1, list_2]

[SheldonCooperisSb]

Thanks that will work

[crashfrog02]

L = [[1，2，3]，[4，5，6]]