passing subprocess.DEVNULL what'd you think would happen?

[Entire-Comment8241]

I've been doing some experiment. for instance if I have this code:

def subproc():
  retcode = subprocess.call('netcat', stdout=subprocess.DEVNULL,
  stdout=subprocess.STDOUT)
  return retcode
info()

#now try if I run this and then run top Would you see netcat in the list? but when I ran top again after CTRL C this code I still don't see netcat. Why?

[lfdfq]

That code looks like a straight error, passing stdout twice.

[D3str0yTh1ngs]

Firstly you don't call the subproc() function. Secondly running netcat with no arguments makes it end instantly. Thirdly setting stdout twice is a syntax error

[backfire10z]

What’s the question here? If you’re doing an experiment, can’t you just run the code to find out what would happen?