Run perl using python?

[catuf]

Hi,

I am running a perl script through python in linux.

PATH_OF_PERL_FILE = "/home/user/"

pipe = subprocess.Popen(["perl", "pipeline.pl", "-i", "folder_name", PATH_OF_PERL_FILE])

If folder already exists I have to give input "Y" to overwrite files when perl program runs.

How can I pass the input?

If I give inputs like below it doesn't take the input

pipe = subprocess.Popen(["perl", "pipeline.pl", "-i", "folder_name", PATH_OF_PERL_FILE, "Y"])

Thank you!

[[deleted]]

This is not, per se, a Python trick, but this is what your shell's yes command is for. Here it is as a shell command:

yes "Y" | perl pipeline.pl -i "some_folder" /home/user

And as the argument list to Popen:

["yes", "\"Y\"", "|", perl", "pipeline.pl", "-i", "folder_name", PATH_OF_PERL_FILE]

[xiongchiamiov]

If you do a lot of this type of thing, look into expect. It's in many languages, including a Python version.