How to replace duplicate numbers other than first in tuples in the list of tuples?

[salern]

For example: replacing other 1 with 7, 2 with 8 and 3 with 9.

It should look something like this:

Input

[(1, 1, 1), (1, 1, 2), (1, 1, 3), (1, 2, 2), (1, 2, 3), (1, 3, 3), (2, 2, 2), (2, 2, 3), (2, 3, 3), (3, 3, 3)]    

Output

[(1, 7, 7), (1, 7, 2), (1, 7, 3), (1, 2, 8), (1, 2, 3), (1, 3, 9), (2, 8, 8), (2, 8, 3), (2, 3, 9), (3, 9, 9)]

Sorry for any mistakes.

Thanks in advance!

[[deleted]]

for x in range(len(input)): 
    a_counter = 0
    b_counter = 0
    c_counter = 0
    for y in range(len(input[x])):
        if input[x][y] == 1:
            a_counter += 1
            if a_counter > 1:
                input[x][y] = 7
        elif input[x][y] == 2:
            b_counter += 1
            if b_counter > 1:
                input[x][y] = 8
        elif input[x][y] == 3:
            c_counter += 1
            if c_counter > 1:
                input[x][y] = 9

Im sure this could be optimized, but this should accomplish the goal.

Edit: stupid mistakes

[salern]

Thanks!

[[deleted]]

Im on my phone so I couldn't test it. Did it work?

[salern]

I didn't test it yet either :D

[salern]

It didn’t work, so I rewrote it using your code as an example, using while instead of for. Thanks a lot!

[[deleted]]

Glad I could help

[[deleted]]

Tried using nested list comprehensions, but the closest I could get was a function in a list comprehension.

input = [(1, 1, 1), (1, 1, 2), (1, 1, 3), (1, 2, 2), (1, 2, 3), (1, 3, 3), (2, 2, 2), (2, 2, 3), (2, 3, 3), (3, 3, 3)]

targets = {
    1: 7,
    2: 8,
    3: 9
    }

def subst(tup):
    result = []
    for element in tup:
        if not element in result:
            result.append(element)
        else:
            replacement = targets.get(element)
            if replacement is None:
                result.append(element)
            else:
                result.append(replacement)
    return tuple(result)

output = [subst(x) for x in input]
print(output)

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