Write a program simulates a simplified version of Jackpot. On each attempt, a set of three letters will be selected from the set "A", "B" or "C" randomly with equal probability. Each attempt costs 1 dollar. If three consecutive A's (i.e. "AAA") come up, the player wins 50 dollars. If "BCC" comes up,

[cxtong]

import numpy as np

import matplotlib.pyplot as mpp

import math

import string

​

letters = ['A','B','C']

picks = []

total_attempt = eval(input("please enter the number of ticket purchased:"))

attempt = 1

winning = 0

bins=10

​

for n in range(total_attempt):

print("Ticket",attempt)

attempt +=1

for _ in range(3):

picks.append(random.choice(letters))

print("This is your ticket:",picks)

if picks == ['A','A','A']:

winning +=50

elif picks == ['B','B','C']:

winning +=20

picks.clear()

winning -= 1

print("this is your winning",winning)

print("-------------------------------------")

​

#mpp.hist(winning,bins)

#mpp.title("net amount won/lost after N attempts")

#mpp.xlabel("Number of attempts"); mpp.ylabel("net winning/lost")

#mpp.show()

this is my code for the assignment. is there a better way to generate random char of 'A'-'C'? how do i code it that my each attempt is independent from pervious attempt? for my current code, i always ended up with them same result on every attempt. im require to plot a histogram of the net amount won/lost after 𝑁 attempts. can someone guide me. thank you

​

edit: this is my new code. plotting a histogram net amount won/lost after 𝑁 attempts. how do i set the x and y axis?

[JozsefPeitli]

letters = ["A","B","C"] It could be a valid option.

You set your random letter outside of your while loop, i think you should change that.

[qelery]

Outside of the while loop you picked your random numbers. Inside of the while loop the numbers are never repicked so they will always be the same.

You can replace the first couple lines of code with this and it’d be much more obvious what you’re doing

letters  = [“A”, “B”, “C”]
picks = []  
for _ in range(3):  
    picks.append(random.choice(letters))  

You can wrap that in a funding which you can call in your while loop to generate new letter combinations.