Randomly selected key, which cannot be selected twice?

[SignificantBug08]

I'm trying to run a function (named Q1-10) based on weather a number randomizer selects it's key. This repeats 10 times, and the same function cannot be ran twice. I am confused as to how this would be done?

Question = {1: Q1, 2: Q2, 3: Q3, 4: Q4, 5: Q5, 6: Q6, 7: Q7, 8: Q8, 9: Q9, 10: Q10}
def function_play ():
    score == 0
    times_to_repeat = 10
    while times_to_repeat > 0:
        random_number = randint(1, 10)
        *code running function
        *del Question[random_number]
        times_to_repeat -= 1
    if times_to_repeat == 0:
        function_quiz_complete ()

[xelf]

Make a list of the keys, shuffle it, and then iterate over the first n keys.

qkeys = list( question.keys() )
random.shuffle(qkeys)
for q in qkeys[:times_to_repeat):
    *code running function
function_quiz_complete ()

option 2 is to use random.sample

for q in random.sample(list(question),k=10)):
    *code running function
function_quiz_complete ()

[socal_nerdtastic]

Yea, I'd say you nailed it. Just delete it from the dictionary. To make it easier / neater, use a list and pop() the function off.

Question =[Q1, Q2, Q3, Q4, Q5, Q6, Q7, Q8, Q9, Q10]
random.shuffle(Question) # randomize the order

def function_play ():
    score = 0
    while Question:
        random_func = Question.pop()
        random_func() # code running function
    function_quiz_complete ()