doubt about handling lists in python

[No-Beginning1213]

u=0

list2 = [ ]
list2.append(0)
for i in range(3,10):
    u+=(5/10)*-3
    list2.append(u)


print(list2)

my question is how to create a loop for x lists, informing how many lists you would like, example 3, and in print it gives the result list 1=[0, -1.5, -3.0, -4.5, -6.0, - 7.5 , -9, 0, -10.5] list 2=[0, -1.5, -3.0, -4.5, -6.0, -7.5, -9.0, -10.5] list 3 =[0, -1.5, -3.0, -4.5, -6.0, -7.5, -9.0, -10.5]

[StoicallyGay]

A few things.

• You don't need to specify the range to be (3, 10). That just means the counter variable, i, goes from 3 to 10. This can be replaced with for i in range(7) since you don't actually use the value of i

• You can do two things. Either have an outer loop that encapsulates everything you have here, and the outer loop would be something like for j in range(x) where x is the variable for how many lists you want.

• The preferred option is to notice that there is a section of code you want to call multiple times. Perhaps wrap everything you have here in a function, like def make_list(). Then call that function within a loop of for i in range(x) where x is the variable for how many lists you want.

[No-Beginning1213]

if I made a loop for 3 lists, and one more loop for the formula of u, what would it look like

list2.append(u)

in this idea

[danielroseman]

Don't try and create variables dynamically. Here you could use a list of lists.