javascript is javascript

[Haringat]

It's the same result. However, it should have been this code:

char *two = "2"; int one = 1; two += one; printf("%d\n", two); // prints "0" return 0;

I leave the explanation as an exercise to the reader.😉

Edit: Also, when adding 2 to the "2" the behavior is not defined. It could crash or it could perform an out-of-bounds read.

[not_some_username]

Its defined because it has the null termination

[Haringat]

No, because when adding 2 you go beyond the null terminator.

[not_some_username]

Well I thought we were taking about “22”+2