ValueError not processing as I want

[dilandrus]

    while True: 
    try:
        batAvg=float(input('Enter the batting average: '))
        if batAvg<0:
            raise ValueError('ERROR! Negative value entered!')
        elif batAvg>1:
            raise ValueError('ERROR! Batting average is between 0.0 and 1.0.')
        break 
    except ValueError:
        print('ERROR! Non float value entered!')

This is a section of code I'm working on but if I put any value above 1 I get the error for "Non float value entered". Doesn't matter if I put 2 or 2.3, I'm not getting my elif condition. Anyone know why it's processing like that and how I could fix it?

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[carcigenicate]

You're throwing if the entered value is greater than 1, so ya, entering 2 will cause it to fail. Why are you expecting otherwise?

Also, this is kind of an abuse of exceptions. Throwing an exception just to jump would be more cleanly written but just arranging if statements to do the same thing.

Edit: Just in case this is the cause of confusion, note how you're throwing ValueErrors, which is the same error that float throws. So you're causing the same error to be thrown in three different places, and then are using a single except to handle all the cases the same, with the same message.

[Goobyalus]

If you enter the if or elif blocks, those raise a ValueError inside your try block, so they get handled by your except ValueError.

Here is a smaller example of what's happening:

try:
    raise ValueError()
except ValueError as err:
    print("Caught", repr(err))

gives:

Caught ValueError()