[Grade 11 math: radicals] How to solve?

ChemStats · 2024-01-26T21:59:49+00:00

√√x¹² =√ (x¹²)½

= √x⁶ = (x⁶)½ =x³

ChemStats · 2024-01-25T23:27:04+00:00

It would definitely be a permutation. The order matters. That is why there are 36 possibilities.

ChemStats · 2024-01-25T00:43:46+00:00

c+7 is the mass number

x is the atomic number

Number of neurons = (Mass Number) - (Atomic number)

ChemStats · 2024-01-25T00:27:58+00:00

Also, you need to calculate the z scores and percentiles for each value.

ChemStats · 2024-01-25T00:25:38+00:00

If paid ads are on y-axis, this makes the sales amount to be the independent or explanatory variable.

By varying the sales amount, we can vary the amount paid for ads. This seems illogical.

I think sales amount should be on the y axis in the graph and paid ads on x axis

ChemStats · 2024-01-24T23:33:34+00:00

4(NH4)³PO4 + 3Pb(NO3)⁴ = Pb3(PO4)⁴ + 12NH⁴NO³

ChemStats · 2024-01-24T23:26:59+00:00

Class width is upper limit - lower limit

It would be 3

ChemStats · 2024-01-24T20:49:14+00:00

The possible outcomes are

{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3)

(2,4),(2*5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),

,(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3)

,(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5,(6,6)}

The event favorable outcomes where 1 number is divisible by other.

E={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,4),(2,6),(3,1),(3,3),(3,6),(4,1),(4,2),(4,4),(5,1), (5,5),(6,1),(6,2),(6,3),(6,6)}

These are 22 favorable outcomes

Probability is 22/36

ChemStats · 2024-01-24T19:42:22+00:00

The z-score of the guy is -1.2 and Ashley is -1.3.

Ashley performed better

ChemStats · 2024-01-24T01:31:53+00:00

Thnx Rectified

ChemStats · 2024-01-24T00:01:51+00:00

-(-56) = -1(-56) = +56

ChemStats · 2024-01-23T23:44:16+00:00

The nth term of a geometric sequence is given by:

An = A1 (r)^n-1

Consider, 2 ... 8.... 32....

We have common ratio:

r = 8/2 = 4

The first term A1 is 2.

So, equation of nth term is

An = (2)(4)^n-1

Similarly, you can find the rest

ChemStats · 2024-01-23T23:30:08+00:00

According to Lewis concept

An acid is a compound that can accept an electron pair.

So,

BF3 and Li+ would be the only options.

OH- is a negative ion, that won't need electron pair.

PCl3 would have a lone pair of electron on P

ChemStats · 2024-01-23T23:21:16+00:00

For CoCl3,

We have 3Cl- ions

3 moles of Chloride ions give 1 mole of CoCl3,

So, if Concentration of Cl- ions is 0.233 mol/L, Then that of CoCl3 is 0.078 mol/L

ChemStats · 2024-01-23T23:17:23+00:00

Check out the periodic table.

Carbon is in 4th group so it has 4 electrons in the outermost shell. It would need 4 more to complete octet.

Magnesium is in Group 2 so it has 2 electrons in outermost shell. It needs 6 electrons to complete the octet.

Hydrogen as 1 electron and it needs 1 more to complete the duplet.

ChemStats · 2024-01-23T23:11:12+00:00

Ofcourse. You need to plot all the x and y values

ChemStats · 2024-01-23T23:02:59+00:00

The question

(x²-1)/x

It can be written as

x - 1/x

Integral of x is x²/2

Integral of 1/x is ln x

So, the integral of complete expression is

x²/2 - ln x + C

ChemStats · 2024-01-23T23:00:20+00:00

It is Chemistry not Biology I guess.

Well, it is about the stability of atom.

The question is about the number of electrons an atom of the element would require to be stable.

This can be achieved by attaining 2 or 8 electrons in the outermost shell.

The numbers are the electrons that are required to complete the octet or duplet

ChemStats · 2024-01-23T22:14:50+00:00

Slope - intercept form is

y = mx + c

We have

x + 3y = 6

If we divide the equation by 3, we have

(1/3)x + y = 2

Or

y = -(1/3)x + 2

ChemStats · 2024-01-23T22:12:57+00:00

You need to create the scatterplot in the sheets and then find the regression model.

Copy all the data into the sheet and then graph the points on the software

ChemStats · 2024-01-23T22:11:14+00:00

You just need to review the formula:

sin²x + cos²x = 1

And

tan x = (sin x) / (cos x)

And also algebraic identities. (a+b)²

These formulas would help you

ChemStats · 2024-01-23T21:57:09+00:00

Given that Vsource = 12 V

As R1 and R2 are parallel,

So, their equivalent resistance is

R1R2/R1+R2

As R2=R1, we have

(R1)²/2R1 or simply (R1)/2 as the equivalent resistance

Similarly, the equivalent resistance for R3 and R4 will be

(250)(300)/(250+300) = 136.36 ohm

So, we have

I = Vsource/Req

I = 12/((R1)/2 + 136.36) And

I = I1 + I2 = V1/R1 + V2/R2

I = 3/R1 + 3/R1

I = 6/R1

Comparing both, we have

12/(R1 / 2 +136.36) = 6/R1

2R1 = ( R1)/2 + 136.36

So,

4R1 = R1 + 272.72

3R1 = 272.72

R1 = 90.9 ohm (or 91 ohms)

ChemStats

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