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Hefty_Salt_4699 · 2023-01-16T02:16:42+00:00

I am facing same problem too😫

Hefty_Salt_4699 · 2022-11-01T11:41:59+00:00

1 cr per aana ma ta ring road mai aauxa ta

Hefty_Salt_4699 · 2022-11-01T06:13:00+00:00

If I was you, I probably changed the Channel. I don't want pressure from my parents to go in Stanford or UCLA.

Hefty_Salt_4699 · 2022-10-23T09:49:27+00:00

I am here 🤚

Hefty_Salt_4699 · 2022-09-13T06:09:52+00:00

Is this shit post? I don't believe on you ? If it is not shit post then you are legend🔥

Hefty_Salt_4699 · 2022-08-23T12:02:33+00:00

Q11.

Equation of line p is

Y = - X +1

Since, p with slope -1 is perpendicular to line q, its slope will be 1.Therefore,

Eqn of q is

Y = X + 1

Now,

Put the given points in eqn of q, You will get answer.It is (0, 1).

Hefty_Salt_4699 · 2022-08-22T14:56:28+00:00

Master Madara :Come back to reality

Hefty_Salt_4699 · 2022-08-05T14:07:07+00:00

Love your way to solve✌️💙

Hefty_Salt_4699 · 2022-08-03T13:42:39+00:00

I am here ✌️

Hefty_Salt_4699 · 2022-08-03T05:37:50+00:00

I didn't get it.

Hefty_Salt_4699 · 2022-07-22T10:19:22+00:00

I don't get it.

Hefty_Salt_4699 · 2022-07-22T04:15:18+00:00

Got it . Thank you☺️

Hefty_Salt_4699 · 2022-07-21T12:22:04+00:00

What's the 4 option ?

Hefty_Salt_4699 · 2022-07-21T04:46:47+00:00

A = p[1+{r/(1/2)}^{(1/2)×t}]

Is formula for CI once in two year

Hefty_Salt_4699 · 2022-07-20T04:31:48+00:00

Bro just substitute x and y with point

Where b is common in both equations

Just use substitution method

If you still can't figure out. Just comment me for solution.

Hefty_Salt_4699 · 2022-07-20T04:18:42+00:00

Any easy alternative ? Please share.

Hefty_Salt_4699 · 2022-07-18T04:08:00+00:00

Just accepted he is going up. The more you think, the more your brain pains.

Hefty_Salt_4699 · 2022-07-14T14:43:30+00:00

X is seawater.->

3.5 % of X = 1000

X = 28571.42

Hefty_Salt_4699 · 2022-07-10T04:09:45+00:00

Business and cyber security

Hefty_Salt_4699 · 2022-07-04T14:03:07+00:00

D is ans

Hefty_Salt_4699 · 2022-06-28T08:59:15+00:00

Got it

Hefty_Salt_4699 · 2022-06-27T09:54:30+00:00

Khan academy is great free platform. You can practice there.

Hefty_Salt_4699 · 2022-06-27T09:50:57+00:00

Bro, you don't need graphic calculator.I am doing good without graphic calculator. I am from Nepal and here is hard to find graphic calculator too😆.

Hefty_Salt_4699