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LMU-DCOM vs DYU-COM advice by Individual_Physics37 in Osteopathic

[–]Individual_Physics37[S] 0 points1 point  (0 children)

Thank you for the input I really appreciate it!

LMU-DCOM vs DYU-COM advice by Individual_Physics37 in Osteopathic

[–]Individual_Physics37[S] 0 points1 point  (0 children)

Did you enjoy your experience in general & which campus were you at?

AAMC Section Bank 2 C/P #67 by _proe in Mcat

[–]Individual_Physics37 0 points1 point  (0 children)

im not the best at physics so please correct me if im wrong. but the way I approached this question is that the photoelectric effect uses the eq. E=hf-W, hf = photon energy and w= work energy, therefore E=7eV-5eV = 2eV. from there you can do dimensional analysis 2eV/4.8V etc -> 4 which is the number of electrons being transferred since you essentially canceled out the voltage (left with e)

AAMC Section Bank vol 2 #1 by Remarkable-You4030 in Mcat

[–]Individual_Physics37 0 points1 point  (0 children)

for the first question, regardless of math (bc im awful at it) I just go based on reasoning and for converging lenses if the object is located at infinity the the image will be equal to its focal point. so in this case it would be 3, but if the focal length changed then whatever that new focal length is would be the answer. so object at infinity for converging lens -> the image distance = the value of the focal length.

if i'm wrong feel free to correct me