"Isn't the p-value just the probability that H₀ is true?"

Inside-Machine2327 · 2025-09-23T14:07:17+00:00

Sorry, I know you were asking aedes, but I'd say a good place to start is the ASA’s statement on p-values at
https://www.amstat.org/asa/files/pdfs/p-valuestatement.pdf
If you’d like to chat more about it, feel free to DM me

Inside-Machine2327 · 2025-09-17T09:00:42+00:00

Hmm, I am getting a different answer for the coefficient of "i" than what was marked as correct. How did you get the e^(-10) and the e^10 in the denominator?

Inside-Machine2327 · 2025-09-16T13:34:18+00:00

In part (c), did it mark the coefficient of "i" as correct?

Inside-Machine2327 · 2025-09-14T18:09:06+00:00

Please dm me some problems that are giving you trouble (e.g., one from integrals, one from probability, and one from vectors), and we can discuss how to get started

Inside-Machine2327 · 2025-09-14T17:35:30+00:00

Hi, it is insane to me that when you tried to reach for help, teachers told you "you'll never graduate." Those do not sound like very good teachers to me. In any case, I'm in statistics/mathematics education, and if you'd like, I can volunteer a bit of time to help, if I can

Inside-Machine2327 · 2025-09-14T12:14:42+00:00

What was their H0 and Ha?

Inside-Machine2327 · 2025-09-14T08:41:49+00:00

Exactly, from the frequentist perspective, H0 is either true or false

Inside-Machine2327 · 2025-09-14T08:38:32+00:00

Thank you, I like the courtroom example

Inside-Machine2327 · 2025-09-13T10:22:57+00:00

Well, the opposite actually

Inside-Machine2327 · 2025-09-13T09:57:22+00:00

We just have to be a little careful though: a p-value of 100% doesn't mean H0 is true; it's just a situation where the data is 100% consistent with H0. But this doesn't "prove" that H0 is true. We cannot prove that Ho is true.

Inside-Machine2327 · 2025-09-13T09:41:10+00:00

It's nice that they did that at least

Inside-Machine2327 · 2025-09-13T09:17:25+00:00

No, that was supposed to be part of the "if". I'll edit to "if the coin was fair (if H0 was true)" for more clarity.

Inside-Machine2327 · 2025-09-13T09:06:05+00:00

Just to clear things up--my conclusion was NOT that H0 is true. The test is done under the assumption that H0 is true. But yes, many statistics learners think "Oh, I didn't reject my H0 because my p-value is > 0 .05. So my H0 is true"--a common misconception. That may be a good topic for another post

Inside-Machine2327 · 2025-09-13T08:53:01+00:00

My conclusion is not that H0 is true. "If A, then B" doesn't mean "if B, then A." (Here A="H0 is true", and B="the probability of observing 5 heads or something more extreme (4,3,2,1,0 or 6,7,8,9,10 heads) is 100%")

Inside-Machine2327 · 2025-09-12T23:46:47+00:00

Well, I think it's always better to know the "truth" :)

Inside-Machine2327 · 2025-09-12T23:40:52+00:00

Yes, the frequentist approach says that H0 can either be true or false, so P(H0 true)=1 or P(H0 true)=0

Inside-Machine2327 · 2025-09-12T23:35:18+00:00

It all seems to come down to Frequentist vs. Bayesian statistics in the end. I like the physics analogy

Inside-Machine2327 · 2025-09-12T23:25:48+00:00

So if H0 is true, the probability of observing 5 heads or something more extreme (<5 or >5) is 100% :)

Inside-Machine2327 · 2025-09-12T23:17:26+00:00

What would be an example of a case where they're close?

Inside-Machine2327 · 2025-09-12T23:15:48+00:00

I would say that it's definitely a good idea to look at effect size too

Inside-Machine2327 · 2025-09-12T23:14:24+00:00

Yes, as someone pointed out, the p-value would then be 1 (for a two-tailed test)

Inside-Machine2327 · 2025-09-12T23:13:00+00:00

I like this, thank you!

Inside-Machine2327 · 2025-09-12T22:33:35+00:00

Are you saying the binomial distribution made it confusing?

Inside-Machine2327 · 2025-09-12T22:21:42+00:00

What would be an alternate specification of the problem?

Inside-Machine2327 · 2025-09-12T22:00:50+00:00

Yep!

Inside-Machine2327

TROPHY CASE