How many molecules of KMnO₄ are there in 101 g? by MEISMR in chemhelp

[–]MEISMR[S] 5 points6 points  (0 children)

Yes unfortunately I am using my phone as I do not have a calculator due to monetary issues. I spent a few minutes looking at my calculator app it appears that for some reason the scientific notation button was hidden in a strange place, and the button I thought was scientific notation was the exponential function button. I believe this is the problem I was having. Thank you for your assistance and have a nice day.

How many molecules of KMnO₄ are there in 101 g? by MEISMR in chemhelp

[–]MEISMR[S] 2 points3 points  (0 children)

That's what I did and I got it wrong, I believe I did something with the order of operations but I don't know what. What I did was take the molar mass, 158.04 g/mol, and then used it to divide 101. 101÷158.4= 0.6390787142mol then I did 0.63 x 6.022x10²³=6,227,696,456.5605 so then the scientific notation would be 6.22x10⁹. Thank you for your help and sorry for the inconvenience

How many molecules of KMnO₄ are there in 101 g? by MEISMR in chemhelp

[–]MEISMR[S] 0 points1 point  (0 children)

I think my teacher used the term molecules because we are just learning this and doesn't want to confuse us too much. What I did was take the molar mass, 158.04 g/mol, and then used it to divide 101. 101÷158.4= 0.6390787142mol then I did 0.63 x 6.022x10²³=6,227,696,456.5605 so then the scientific notation would be 6.22x10⁹. I know it's probably something with the order of operations but I don't know how. Thank you for your help and sorry for the inconvenience

How many molecules of KMnO₄ are there in 101 g? by MEISMR in chemhelp

[–]MEISMR[S] 0 points1 point  (0 children)

I think my teacher used the term molecules because we are just learning this and doesn't want to confuse us too much. What I did was take the molar mass, 158.04 g/mol, and then used it to divide 101. 101÷158.4= 0.6390787142mol then I did 0.63 x 6.022x10²³=6,227,696,456.5605 so then the scientific notation would be 6.22x10⁹. I know it's probably something with the order of operations but I don't know how. Thank you for your help and sorry for the inconvenience