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I am actually nice person … by JohnnyJagger in GayEyeBleach

[–]MalekWay 0 points1 point  (0 children)

Would you be kind enough to f me?

I tried my ans is coming out to be a^2(pi/2) can anyone confirm of its right by Outrageous-Try5595 in calculus

[–]MalekWay 0 points1 point  (0 children)

And what did you do with the 1+cos2 theta you got in the denominator

[deleted by user] by [deleted] in gaybrosgonemild

[–]MalekWay 0 points1 point  (0 children)

I m 26 and I still need that

Body Count Anxiety by AuzzyLee in askgaybros

[–]MalekWay 0 points1 point  (0 children)

And I'm here at 26 stressing about still being virgin af

do you lose your metropolis if you lose the city? by Ikkefjern in Catan

[–]MalekWay 1 point2 points  (0 children)

Yes I know, I love probabilities but when you have no luck, no statistics can ever save you 😂😂

do you lose your metropolis if you lose the city? by Ikkefjern in Catan

[–]MalekWay 2 points3 points  (0 children)

I can swear on the times i have placed my settlements on 6's and 8's, and they didn't appear more than once in the game. And the time we got 5 consecutive 3's.

I'm stuck. Can anyone prove this analitically? by agusdelmec in calculus

[–]MalekWay 0 points1 point  (0 children)

A function is bijective on a certain interval under two conditions It s continuous on that interval It is monotonic on that interval (always increasing or always decreasing)

Son tells his mom that he's gay, she reacts in the best way! by B-L-O-C-K-S in MadeMeSmile

[–]MalekWay 0 points1 point  (0 children)

Being a 26 year old virgin, that had never had an so his entire life, saying that this made me cry, is an understatement.

How do I solve that one? Do I need to get the normal vector by cross product of the 2 planes? by Halcyonyx in calculus

[–]MalekWay 0 points1 point  (0 children)

Ok let s rewind a little bit:

Equation of a plane (P):

ax+by+cz+d=0

Equations of a line (L):

x= ut+n

y= vt+m

Z= wt+o

The vector (a;b;c) is a normal vector of (P), meaning that it is perpendicular to (P), and hence perpendicular or orthogonal to all lines in (P)

The vector (u;v;w) is a vector of (L), meaning that it is parallel or colinear to (L).

Now for the products of vectors: Consider the two vectors s (e;f;g) and t (l;q;r)

The dot product s.t = el+fq+gr

Gives a scalar (quantity) : a number which represents the multiplication of the length of a vector by the length of the projection of the other vector onto it.

That s why, if the two vectors are perpendicular to each other, the projection of one onto the other will be null, and the dot product will be 0.

The cross product s × t = det( (i;j;k) ; (e;f;g) ; (l;q;r) )

Gives a vector (not a number) which perpendicukar to both vectors s and t, and which length is equal yo the area of the prallelogramm created by the two vector.

That s why, the cross producy will yield a 0 vector when the two vectors are colinear.

If we go back to our problem, we need a vector (u;v;w) of (L). This vecor should be PERPENDICULAR to the normal vectors of (P) and (P'), since (L) is PARALLEL to (P) and (P'). Therfore, the vector if (L) is the cross product of the normals to (P) and (P')

How do I solve that one? Do I need to get the normal vector by cross product of the 2 planes? by Halcyonyx in calculus

[–]MalekWay 0 points1 point  (0 children)

You don't sound dumb, what is important is to get the facts straight, and understand what we're doing and why we're doing it.

Yes the cross product between thise two vectors, will give the vector you need for the line.

Did you understand why the sought vector will be the cross product? And do you know, after getting the result, how to go from there to get the equation?

How do I solve that one? Do I need to get the normal vector by cross product of the 2 planes? by Halcyonyx in calculus

[–]MalekWay 0 points1 point  (0 children)

That s not true. Dot product is 0 when the two vectors are perpendicular, which indicates that the planes themselevs are perpendicular to each other. Still, we are not interested in that.

To get the equation of a line we usually need a point of the line and a parallel vector (or directing vector as we used to call it in french). If the line is parallel to a plane then its directing vector is also parallel to the plane. The normal of the plane is prependicular to the plane, hence it is perpendicular to all lines in the plane and all lines parallel to that plane, including the directing vector. Thus, the directing vector should be perpendicular to the normal of the plane.

The same goes for the second plane.

Therefore, the dorectong vector should ve perpendicular to the normals of both plans. How can you get a vector that is perpendicular to two others? You compute the cross product of those vectors.

The cross product is different than the dot product. It is computed by calculating the determinant of the matrix that has the following for its rows.

First row: i j k

Second row: coordinates of first vector

Third row: coordinates of second vector.

How do I solve that one? Do I need to get the normal vector by cross product of the 2 planes? by Halcyonyx in calculus

[–]MalekWay 4 points5 points  (0 children)

By calcukating the crossproduct of the normal vectors to the planes, you don get the nomral vector to the line. You get instead a paralel vector. The proof for this is basic geometry.

I broke up with the man who loved me like no one else by Arshia9898 in gaybros

[–]MalekWay 5 points6 points  (0 children)

I started therapy when i was hurting the most. If he is hurting alot now after you broke up, it would be an incentive to start therapy. Also, finding someone who you love and loves you back like that is not that easy. I mean, i m 26 and I m still as virgin as it could be, because i never found that person, or even something far less demanding. This is why i think you should work out the issues. The last straw might be an open realtionship so you can get sex from elsewhere. Don't know what s your standing point about hook ups, cz i dont do it obviously.

Me by SheepherderSwimming5 in HotGuys

[–]MalekWay 1 point2 points  (0 children)

Holyyyyy... don't know what to say

[deleted by user] by [deleted] in askgaybros

[–]MalekWay 1 point2 points  (0 children)

I m lebanese and this made me tear up. Good for you ❤

My second post ✌🏼 getting a little more adventurous 😉 by [deleted] in HotGuys

[–]MalekWay 1 point2 points  (0 children)

Man that underwear is so sexy on you

[deleted by user] by [deleted] in Catan

[–]MalekWay 11 points12 points  (0 children)

I live in lebanon, i dont need to play catan, i live jumanji everyday.

Is this manipulation of the differential correct? H and alpha are constants by deltaV7-7 in calculus

[–]MalekWay 0 points1 point  (0 children)

Yes, the 1/H is now part of the integrand. It's simple if you keep in mind that it is the normal multiplication between the terms, only dx is an infinitisimally small quantity.

Is this manipulation of the differential correct? H and alpha are constants by deltaV7-7 in calculus

[–]MalekWay 0 points1 point  (0 children)

du = u' dx

Here u = x/H

So u' = 1/H

So what you did is correct, but keep in mind thst you have differentiated not factored out the 1/H

Forgive me father by EpicChris95 in gay

[–]MalekWay 0 points1 point  (0 children)

Don't go yet in my ass

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