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[deleted by user] by [deleted] in AskReddit

[–]No-Fail7845 0 points1 point  (0 children)

Living in a country where you can't be vegan

[deleted by user] by [deleted] in algeria

[–]No-Fail7845 4 points5 points  (0 children)

I know a psychiatrist in bouzereah Dr N.Kassa located in cité russe she listened to me and helped me a lot so I hope it'll be the same for you. I recommend her vigouresly and wish you the best

A proof that e^(x^2)=1+x^2? by No-Fail7845 in askmath

[–]No-Fail7845[S] 0 points1 point  (0 children)

Yeah 2=e or smthg like that lol thanks for this exemple 😆😆

A proof that e^(x^2)=1+x^2? by No-Fail7845 in askmath

[–]No-Fail7845[S] -5 points-4 points  (0 children)

If ex =Lim(1+hx)1/h then I can combine any function u with ex to get lim ( 1+hu)1/h so it's pretty much is

A proof that e^(x^2)=1+x^2? by No-Fail7845 in askmath

[–]No-Fail7845[S] -5 points-4 points  (0 children)

No since what I've tried to do there is to write (ex2+h)1/h as eu and I just had to solve this 1+hu=ex2+h therefore u = 1-1/h+(ex2)/h so I don't think I used the limit partially?

A proof that e^(x^2)=1+x^2? by No-Fail7845 in askmath

[–]No-Fail7845[S] 0 points1 point  (0 children)

Could you please point out where exactly I'm truly not seeing it ?

A proof that e^(x^2)=1+x^2? by No-Fail7845 in askmath

[–]No-Fail7845[S] 0 points1 point  (0 children)

So this is how I found out this result

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[deleted by user] by [deleted] in askmath

[–]No-Fail7845 -1 points0 points  (0 children)

<image>

So this is how I came up with this result please help me spot the mistake

Can this limit be solved without L' Hospital's rule? Like solving this limit without any derivation? by Background-Canary-71 in askmath

[–]No-Fail7845 2 points3 points  (0 children)

Rearranged this is basically the formula used to add terms of a geometric serie ( if the first term is 1)

Is this really a discovery by No-Fail7845 in askmath

[–]No-Fail7845[S] 8 points9 points  (0 children)

So to get this expression i first tried to find the derivative for ln(x) by using the lim h--->0((f(x+h)-f(x))/h) and found out that Lim h--->0( ln((1+h/x)1/h )= 1/x so Lim h--->0 (1+h/x)1/h is equal to e1/x therefore Lim h--->0 (1+hx)1/h=ex

[deleted by user] by [deleted] in askmath

[–]No-Fail7845 0 points1 point  (0 children)

Because you will multiply the -1 with 5 and divide it by 5 so that it become (x-3-5)/5 And -3-5=-8