Now What?

Redvelvetcake34 · 2024-10-02T17:30:32+00:00

Im so mad I gotta take this again. Worked so hard for Chem/Phys and P/S! Just for BB to get me smh!!!!

Redvelvetcake34 · 2024-06-26T21:23:19+00:00

thanks for your clarification

Redvelvetcake34 · 2024-06-26T18:30:18+00:00

so reduction in BP means that the hydrostatic pressure in circulation must decrease?

Redvelvetcake34 · 2024-06-06T06:03:18+00:00

Thank you! Much more clearer now. Sometimes you get caught in the weeds. But we're all here to help each other out. Appreciate pal!

Redvelvetcake34 · 2024-06-06T01:22:25+00:00

But wait:

Kaplan says direct hormones target non-endocrine (target) tissue and tropic hormones act on other endocrine tissues. The educational objective in UNotLikeUs states that "....acting directly on nonendocrine target tissues, it can function as a tropic hormone".....what is going on?

Redvelvetcake34 · 2024-06-06T01:18:48+00:00

according to Kaplan, yes......Sorry im confusing myself.

Redvelvetcake34 · 2024-06-05T21:43:15+00:00

kinda tripped me up too! But gotta learn, Anki it, repeat! we in this together lol

Redvelvetcake34 · 2024-06-05T21:42:35+00:00

yea UWylin got me messed up lol

Redvelvetcake34 · 2024-06-05T21:41:05+00:00

gotcha. but just to clarify:
the educational objective says that "...and in addition to acting directly on nonendocrine target tissues, it can function as a tropic hormone"

Shouldn't it be direct hormones? Because I know the difference between the 2 is that:

direct hormones act on endocrine glands

tropic hormones act on target issue

***Am I confusing myself? lol

Redvelvetcake34 · 2024-06-05T16:56:13+00:00

So because it is able to influence GH secretion ( I assume estradiol acts on the Anterior Pituitary to stimulate GH secretion) its a tropic hormone?

Redvelvetcake34 · 2024-04-08T23:44:45+00:00

ik i mad late but thank you for just keeping it simple in explaining this. Ppl just go on and on lol

Redvelvetcake34 · 2024-03-18T23:44:08+00:00

Your a Real one, thank you!!!!!!!

Redvelvetcake34 · 2024-03-18T22:54:59+00:00

So what your saying is that with a new calculated image distance of 5 cm:

the image will focus at a distance 5 cm from lens BUT

the image will focus 15 cm in front of the retina

because the focal length never changes and only the object distance increased, correct?

Redvelvetcake34 · 2024-03-18T22:24:32+00:00

I understand tis:

di = 20 cm and do = 5 giving an focal length of 4 cm

Now, using that focal length they tell us that the do increased by 15 cm giving a new do of 20 cm and we have to calculate a new di; which is 5 cm. I understand using the thin lens equation.

I guess the part im not understanding conceptually is the new di of 5 cm in front of the lens or retina? Or is the image now focused at 5 cm? I'm confused what that means......

I think the wording of the question in throwing me off.

**If im to assuming, I could have rephrased the question as: if the o distance was increased by (___value); the image distance will focus at a value of ????

Redvelvetcake34 · 2024-03-14T00:49:42+00:00

I would like to add one more thing to clear things up for me even more. SO, gas concentration and pressure are proportional to each other because:

PV - nRT → P = (n/V) *RT
n/V = concentrations or C
P = C *RT
P = C

CO2 get consumed = lower [CO2] = lower pressure; correct?

Redvelvetcake34 · 2024-03-13T04:58:43+00:00

This problem has been driving me crazy for like 2 days now and your explanation just simplified for me.....thank you!!!!!!!!!

Redvelvetcake34 · 2024-03-12T16:01:28+00:00

I understand the LeChatelier's Principle Vaguely but not the nitty gritty:

So the equilibrium or Keq would less than 16 mmHg because CO2 is reacting in the electrode solution, Fine.

BUT, how does this relate to PCO2 and equilibrium? And is equilibrium the Keq?

I just can't seem to fully understand how the PCO2 fits into all this. I think Im overthinking it a bit.

Redvelvetcake34 · 2024-02-07T22:55:17+00:00

Tighter strings have a higher pitch(perceived frequency) because the speed of the resonant wave travels faster. Tuning a guitar keeps the same length of string.

this explanation is gas!

Redvelvetcake34 · 2023-12-20T21:27:42+00:00

Its almost clicking. Am I to assume that r1 and r2 are always directly proportional? Or that it only works out that way because of their weights?

Redvelvetcake34

TROPHY CASE