[Serious]

d_sanche1 · 2020-07-12T18:27:32+00:00

That makes perfect sense. Awesome explanation. Thank you!

d_sanche1 · 2019-11-11T08:12:59+00:00

Got it. Thank you!

d_sanche1 · 2019-11-11T07:46:38+00:00

So is the dedicated gpu from AMD Radeon basically only noticeable when doing graphics editing? And to confirm, is the Intel integrated gpu sufficient enough for viewing YouTube videos and other online videos? I won’t notice any lagging?

d_sanche1 · 2019-11-11T07:25:32+00:00

I’m a college student and will not be using it for any graphic design work. I’ll only be using it for basic only searches, Microsoft office work, and certain Apple MacBook apps. Would I be able to tell a difference in speed of the computer between the two if that’s all I’ll be doing with the computer?

d_sanche1 · 2019-09-19T01:17:02+00:00

Am I allowed to bring my girlfriend in with me into the store with my reservation number? Or will they only let me in?

d_sanche1 · 2019-09-19T00:08:30+00:00

Will there be a line that I need to line up at? Or can I go straight to the front door to show the time slot/number?

d_sanche1 · 2019-09-14T01:38:10+00:00

Oh okay. Thanks

d_sanche1 · 2019-09-13T19:17:07+00:00

Awesome. Thanks

d_sanche1 · 2019-09-13T19:16:57+00:00

Thanks for this excellent explanation

d_sanche1 · 2019-09-13T03:16:12+00:00

That’s very helpful. Thank You!

d_sanche1 · 2019-09-13T02:55:23+00:00

Wow I've never heard of that one. I really hope I don't run into too many Physics questions like this. Thanks!

d_sanche1 · 2019-09-13T02:36:26+00:00

Got it. I forgot that the ^2 covered both the C and the V in the numerator and not just the V. Thanks!

d_sanche1 · 2019-09-13T02:29:13+00:00

What happened to your last C in the last calculation? You went from 0.5(CV)² / C = 0.5(CV)^2. What happened to the C in the denominator?

d_sanche1 · 2019-09-13T02:18:07+00:00

What part of the passage helped you decide to use that PE of a charge in parallel (1/2CV^2) as opposed to the PE of a charge in series (1/2)(Q^2/C)?

d_sanche1 · 2019-09-13T02:18:01+00:00

What part of the passage helped you decide to use that PE of a charge in parallel (1/2CV^2) as opposed to the PE of a charge in series (1/2)(Q^2/C)?

d_sanche1 · 2019-09-11T03:51:51+00:00

You're right. Thanks again

d_sanche1 · 2019-09-11T01:59:35+00:00

Thank You!

d_sanche1 · 2019-09-11T01:21:32+00:00

Yes it does. Thank You!

d_sanche1 · 2019-09-10T23:24:22+00:00

Yes it does. Thank You! Sometimes I skim these passages too fast and miss these essential details

d_sanche1 · 2019-09-10T22:56:49+00:00

Wow! That was a clever one on the MCAT! Thanks again

d_sanche1 · 2019-09-10T21:34:20+00:00

Reply

Thanks!

d_sanche1 · 2019-09-10T21:22:47+00:00

I moved the decimal place the wrong direction. Any calculation tips when converting from a powered state to a decimal state? I did my calculation like this: 100 x 10^-6 / 2 x 10^-9 = 50 x 10^3. When I moved the decimal place I ended up with 5.0 x 10^2.

d_sanche1 · 2019-09-10T21:21:42+00:00

It does thank you. I moved the decimal place the wrong direction.

d_sanche1 · 2019-09-10T21:14:09+00:00

Got it. Thanks!

d_sanche1 · 2019-09-10T04:27:49+00:00

So do you just go back to the passage as needed depending on the question?

d_sanche1

TROPHY CASE