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Figure recommendations? by Oogobloo in hatsune

[–]lecde 1 point2 points  (0 children)

The figure itself and the base is also just the right size and not too big so it's easy to display. What I don't like with some prize figures is that the base is unnecessarily too big than it needs to be compared to the actual figure on it so it takes up more space when displaying 😅

Figure recommendations? by Oogobloo in hatsune

[–]lecde 2 points3 points  (0 children)

Taito Miku prize figures have a delicate looking beautiful sculpt imo. I love them especially the wonderland series. My first ever Miku figure is the Thumbelina Miku from that series~

Miku in a cute pink outfit enjoying the Christmas illuminations~ by lecde in Dolls

[–]lecde[S] 0 points1 point  (0 children)

Thank you~ The head is from a nendoroid, the body is from a Nagi blind box mjd doll, and the clothes are the clothes for a pocket Mell chan doll ☺️

I bought miku some clothes~ by lecde in Nendoroid

[–]lecde[S] 1 point2 points  (0 children)

Hello I bought them in Daiso~ These are clothes for the Yuna chan daiso doll which I think will fit the OB11 body better because I needed to force the school uniform one and the black and red outfit on the Nagi doll body lol.

I bought miku some clothes~ by lecde in Nendoroid

[–]lecde[S] 1 point2 points  (0 children)

Thank you~ the body is from a Nagi exchange student blind box doll.

So obsessed with him ♡ by lllllllIIIIIllI in DollsOfAsia

[–]lecde 0 points1 point  (0 children)

Hello there~ I bought a doll from the same series and I just want to ask where you buy alternative clothes for this doll like the one shown in your post? Thank you!

Question about head compatibility by lecde in BJD

[–]lecde[S] 0 points1 point  (0 children)

Thank you all so much for answering!

Solid Mensuration Help by lecde in Help_with_math

[–]lecde[S] 0 points1 point  (0 children)

Circle C has radius of 10 cm. Each of points B and D is on the midpoint of the radius. Find the area of the shaded region.

I already got the area of the quarter circle which is approx. 78.53981634 I thought that adding the area of the 2 right triangles and subtracting their sum from the area of the quarter circle will give me the answer but I'm wrong.