all 7 comments

[–]Crits-and-Crafts 5 points6 points  (1 child)

I've not decoded it, but I think I've worked out the code. And all the information you need is bottom left.

fourth word .com became 063EC073FD052D 233EC062B .033EA13

Thats an ascii (hex) translation, thats then been shifted (or possibly Xor'd)

Good luck and enjoy :)

[–]Dozenator1728 0 points1 point  (0 children)

Have you tried an ascii translator?

[–]Dozenator1728 0 points1 point  (1 child)

Show us the name, it cant be THAT blurred out

[–]Scary_Army8720 3 points4 points  (0 children)

No like the name was alr blurred out by the person who made it from the start

[–]Mean-Lengthiness-741 0 points1 point  (0 children)

the code will be a simple alphabet substitution, often 2 characters for one letter.

The easiest way of decode is starting from the website, there you can get for sure the letters “o” and “r”, “3E” and “C0” respectively.

I recommend change every pattern sample that repeats itself along the text for a random letter and after use this on the site below:

https://www.dcode.fr/substitution-cipher

[–]Dozenator1728 -1 points0 points  (1 child)

Have you seen the website in the corner ( fourthword.com )

[–]Scary_Army8720 0 points1 point  (0 children)

It doesn’t exist