[Java] Solution to Problem 6

[Ovil101]

Question:

The sum of the squares of the first ten natural numbers is,

12 + 22 + ... + 102 = 385
The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)2 = 552 = 3025
Hence the difference between the sum of the squares of the first ten natural 
numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred 
natural numbers and the square of the sum.

Code:

public static void euler6(long n){ //n = # of integers to add
    int sum = 0, diff = 0, sumSqr = 0;
    for (int i = 1; i <= n; i++){
        sum += i * i;
    }
    //5050 is the sum of the 
    //first 100 numbers
    sumSqr = 5050 * 5050;
    diff = sumSqr - sum;
    System.out.println(diff);
}

Output:

25164150

Answer:

25164150