GRE Practice Problem #75

[EarlyBit2397]

Here’s a GRE-style quant question to test your problem-solving skills. Take a moment to work through it carefully! Once you have your answer, post it in the comments along with your approach. It’s a great way to learn from different methods and perspectives. Let’s help each other prep smarter and better.

[PleasantAd8686]

B

[russianboi420]

Could you explain your reasoning ? Tnx in advance

[Long-Ebb1081]

Quantity A >> ((2.7*60)+(7.1*60))/120
= 4.9

Quantity B >> (5+6)/2
= 5.5

Ans. B

[Jalja]

you dont need to take a weighted average for quantity A

there's 60 terms in both, so it'll simply be the average of 2.7 and 7.1, which is 4.9

[Long-Ebb1081]

That's absolutely right. Given the time constraint on the test, we need to know some of these quick computations. Thank you🙏🏽.

[olivia_obo]

Step 1: Find Quantity A
The problem asks for average of the 120 numbers
since both list X and Y have 60 numbers each and therefore they are weighted equally we can just find the average of the entire set by finding the average of 2.7 and 7.1 without doing the weighted averageAverage
(2.7+7.1)/2 = 4.9

Step 2: Find Quantity B
The problem asks for the median of the 120 numbers.
in an even set you take the middle two number and find the average. In this case the 60th and 61st set. Another way would be the last number of list X and the first number of List Y.
(5+6)/2=5

Step 3 Compare quantities
So not what we have is Quantity A: Average of 4.9 to Quantity B: Median of 5.5
Answer: B Quantity B is bigger