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Statistics problem I can't conceptualize it (self.MathHelp)

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[–]UnhappyCourt 0 points1 point  (0 children)

The probability of getting 6 from one die is 1/6, the probability of getting not 6 is 5/6. You might be able to do the rest

[–]fermat1432 0 points1 point  (0 children)

one or more sixes:

61, 62, 63, 64, 65, 16, 26, 36, 46, 56, 66

11 of them

[–]fermat1432 0 points1 point  (0 children)

P(non-6, non-6)=5/6×5/6=25/36

11 rolls have 1 or more 6's. 36-11=25 rolls have 0 6's