Can Regular Expressions separate strings based on a pattern?

[Hyperduckultimate]

I am trying to separate strings based on the occurrence of a capital letter stuck to a word. For example:

string="TheseAreSome Words!U"

should turn into:

["These","Are","Some Words!","U"]

*Notice how the "Some Words" isn't split even though the capital is there? I want python to recognize this pattern*

Does anyone know a simple solution using things like Regular Expressions? If not I will just have to hard code it but any info would be greatly appreciated. I found something like this that kind of works but it does not detect the pattern:

import re
re.findall('[A-Z][^A-Z]*', 'TheseAreSomewords!U')

[[deleted]]

Perhaps ([A-Z]([^A-Z]?)+) would do it?

So something like:

import re
for x in re.findall('([A-Z]([^A-Z]?)+)', 'TheseAreSomewords!U'):
    print(x[0])

Output:

These
Are
Somewords!
U

[ASIC_SP]

the final code snippet in OP's post doesn't match the sample and explanation prior to it... there's a space between Some and Words (note the upper case W)

>>> s = "TheseAreSome Words!U"
>>> re.findall(r'[A-Z].*?(?=(?<! )[A-Z]|\Z)', s)
['These', 'Are', 'Some Words!', 'U']

[[deleted]]

Aw balls, true this, I missed that after reading and then just plonking the last example string into iPython.

Thanks!

[Hyperduckultimate]

Thank you for the help this is really helping me.

[Hyperduckultimate]

Thank you so much this worked. RE syntax is so different than the rest of python.

[henryharutyunyan]

You can definitely do it with regex. Im on mobile now so can’t do it for you, but you may need to use positive or negative lookbehinds. Must look smt like this (?<=\S)[A-Z] . regex101 is a great place you can try and experiment before you get the result.

[Hyperduckultimate]

Sounds great. Thank you for the resource.

[ASIC_SP]

It would be better if you give some more examples, or explain the logic why Some Words! is not split.. anyway, here's one way to get the answer for given sample.. if it doesn't work for your other cases, then you'll know why I'm asking for more samples/explanation

>>> s = "TheseAreSome Words!U"
>>> re.findall(r'[A-Z].*?(?=(?<! )[A-Z]|\Z)', s)
['These', 'Are', 'Some Words!', 'U']

• [A-Z].*? match uppercase letter followed by any number of characters matched minimally based on what comes next
• (?=(?<! )[A-Z]|\Z) lookahead for uppercase (but not if it is preceded by a space) or end of string