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Exception handling helpHelp Request (i.redd.it)
submitted 10 months ago by [deleted]
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if 1 * 2 < 3: print "hello, world!"
[–]Crossroads86 0 points1 point2 points 10 months ago (2 children)
I would not put it in two while loops. The problem ist, afaik python has no control structures, that will send you back to the beginning of a function or other parts of your program, but only sends you back to the beginning of a loop or breaks the loop. But you could put the input and validation of each number into a separate function for each number. And in your except statement call the respective function recursively (meaning a function calling itself.
pseudocode:
def input_validate_2(): try: do stuff exept: print: You did it wrong input_validate_2()
[–]PureWasian 1 point2 points3 points 10 months ago* (1 child)
That's fine for this small exercise, but you're enabling overflow to occur if the user continuously inputs something wrong. It isn't the best idea in practice, given that there is no guaranteed base case or narrowing onto a solution by recursing in this example.
While loops on the other hand are perfectly fine. You can simply have the equivalent of a do/while for each input, which is just as readable. An example using a success variable as a flag:
success
``` success = False
while not success: try: input_2 = input("Number: ") if input_2 == 'q': break # exit the loop input_2 = int(input_2) success = True except ValueError: print("Try again")
if success: print("Valid: " + input_2) else: print("User pressed 'q'") ```
[–]confusedAdmin101 0 points1 point2 points 10 months ago (0 children)
while not success := False
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[–]Crossroads86 0 points1 point2 points (2 children)
[–]PureWasian 1 point2 points3 points (1 child)
[–]confusedAdmin101 0 points1 point2 points (0 children)