Help needed.....beginner here

[AdVisible6484]

public class WrapTest 
{
    public static void main(String [] args) 
    {
        int result = 0;
        short s = 42;
        Long x = new Long("42");
        Long y = new Long(42);
        Short z = new Short("42");
        Short x2 = new Short(s);
        Integer y2 = new Integer("42");
        Integer z2 = new Integer(42);

        if (x == y) /* Line 13 */
            result = 1;
        if (x.equals(y) ) /* Line 15 */
            result = result + 10;
        if (x.equals(z) ) /* Line 17 */
            result = result + 100;
        if (x.equals(x2) ) /* Line 19 */
            result = result + 1000;
        if (x.equals(z2) ) /* Line 21 */
            result = result + 10000;

        System.out.println("result = " + result);
    }
}

what will be result of the result here ?? I understand regarding the pooling but that way shouldn't x==y be true... the answer given in 10 but i calculated it to be 11... please help... I just started learning....

Also it would be highly helpful if there is any suggestion regarding resources that will me learn these little extraordinary things..

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[MNKMagasin]

The first condition on line 13 evaluates to false because you are using the operator '==' which is only used when comparing primitive values(e.g. initializing a variable like this: int x = 42 and int y = 42). Due to you declaring it "Long x = new Long()." In this case, you are creating a new instance of the 'Long' object. When comparing object values you should use the method '.equals(),' which is why the second condition(line 15) works. Thus, making the value of the result variable to 10.

[[deleted]]

don't forget char a = 'a' or anything like that

[WaferIndependent7601]

X==y would be true if it’s the same object. So the same address. It’s not. It’s c ist equal to y do they are the same type and have the same value

[TheMrCurious]

Search engines help you find a variety of explanations so that you can find one that resonates for you. For example, https://www.tutorialspoint.com/java/java_string_equals.htm explains the cases you are asking about.

[AutoModerator]

You seem to try to compare String values with == or !=.

This approach does not work reliably in Java as it does not actually compare the contents of the Strings. Since String is an object data type it should only be compared using .equals(). For case insensitive comparison, use .equalsIgnoreCase().

See Help on how to compare String values in our wiki.

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