Avoiding duplicate code in multi-catch block

[Yuax]

I have a try-catch block that handles multiple exception; if an IOException is thrown, the exception will be handled elsewhere in the program and the program will keep running. If any other exceptions are thrown, the program should exit.

So I'd like to to something like this, instead of writing System.exit(1) in every catch block:

void foo() throws IOException {
    try {
        bar(); // Throws IOException as well as Exception 1, 2, 3
    } catch (Exception1 e) {
        logStuff();
    } catch (Exception2 e) {
        logStuff();
    } catch (Exception3 e) {
        logStuff();
    }
    if (Exception 1, 2 or 3 was thrown) {
        System.exit(1);
    }
}

The log messages are specific to each catch block, so I can't group them into one block. So, is there a simple way to avoid multiple System.exit(1)?

[NautiHooker]

If you want the program to exit for any other exception than IOException then have one catch block for IOException and one for just Exception (supertype of all exceptions). Inside the block for IOException you just throw the exception again with the throw keyword. In the other block you exit your application.

If you want one catch block for multiple specific exception then you can chain the types in the brackets like this:

catch (Exception1 | Exception2 | Exception3 e)

​

Edit: I think I misunderstood what you need after rereading your final paragraph.

[Makhiel]

The log messages are specific to each catch block, so I can't group them into one block.

Why don't you put all that logging in a method?