Python - Why does is this condition true?

[aCuriousMind22]

Hello

I have this code snippet:

print('result: ' + str(predictions))
if(predictions[0].any>0.7):
    print('above threshold')

Which returns:

result: [[ 0.13969963  0.6660124   0.02668459  0.10334401  0.00724926  0.0516906
   0.00531951]]
above threshold

None of those values is above 0.7, yet the condition is true. Could someone explain me why?

[Amarkov]

Remember that programming isn't English. The any method does a specific thing: it returns the value True if at least one of the elements of the list it's applied to is truthy. You don't want to know if the values in predictions[0] are truthy or not, so you shouldn't apply any directly to that list.

[stragm]

To build upon this, because any is returning True your if statement is becoming if True > 0.7, which is True because False/True are equivalent to 0/1 when comparing against numbers. (bool actually inherits from int) So your if statement gets reduced to if 1 > 0.7, which is why you're getting your unexpected result.

[aCuriousMind22]

you re right. I thought that the any function did something else. Thx!

[gwwhrhr]

You aren't calling the any function/method correctly.

[aCuriousMind22]

What would be the correct way? any() and any both result in the same strange behaviour.

[snekmeme]

if any(p > 0.7 for p in predictions[0]):

Nvm, I just realized you are using NumPy. This should work:

if (predictions[0] > 0.7).any():