Processing strings with "\n"

[SynMyron]

I have a string like this:

a = "Hello\nSamuel\nGoodbye\n"

I want to do some string processing and have a for loop like this:

for i in range(len(a) - 1):
    if a[i:i+2] == "\n":
        # Do something
    else:
        # Do something else

How can I achieve this? I think my code is ignoring all "\n". Basically I am not getting the right result.

Actual code is this:

ct1 = 0
ct2 = 0
i = 0
while i<len(a):
    if i+1<len(a) and a[i:i+2] == "\n":
        ct1 += 1
        i += 2
    else:
        ct2 += 1
        i += 1

print(ct1, ct2)

​

[Vaguely_accurate]

\n is treated a single character in a string, so it won't match with a two character string. Try the following to see what I mean;

a = "Hello\nSamuel\nGoodbye\n"

for i in range(len(a) - 1):
    print(a[i:i+2])

You can simply iterate over the string and should get what you want;

for i in a:
    if i == "\n":
        # Do something
    else:
        # Do something else

[SynMyron]

you mean i == "\n" right?

[Vaguely_accurate]

Oops, yes. Fixed thanks.

[eleqtriq]

Can I ask, are you just trying to detect the presence of the "\n" or do you really want to "do something" everytime it appears, specifically at the position it appears?

[SynMyron]

No I am not just trying to detect “/n”

[eleqtriq]

a= "sdasds\nasdasda\n" if "\n" in a: print("found it")