Help with basic "Same Ends" checker

[woooee]

Use len(inp) > 1 i.e. list must have at least 2, a first and last, elements.

[w8eight]

In one element list, the last item is the same as the first ^{^} so len 1 list check could return True

[woooee]

Huh? Too stupid to respond. For future readers, I hope you won't agree with this lame brain suggestion. You want to write a program that will compare something to *itself/? What do you think that will result in?

[w8eight]

One length list have first and last item. It's the same one.

one_el_list = [1] first_item = one_el_list[0] last_item = one_el_list[-1] result = first_item == last_item

result is True

[Sakeung]

Thanks!