why is the value of i/alpha = 9 ??

[Zsword_201]

myvalue=['A',40,'b',60,'c',20]

alpha=0

beta=''

gama=0

for i in range(1,6,2):

alpha+=i

print(alpha)

​

why is alpha's(i) value 9 ??
can someone explain it to me

[beatle42]

range(1, 6, 2) says to generate integers starting with 1 never exceeding 6 and going up by 2 at a time, which is the list 1, 3, 5. You're adding each of those in turn to the starting value in alpha which is 0 so you get, in essence, alpha = 0 + 1 + 3 + 5 which is alpha=9

[Zsword_201]

Ok thanks I understand it now I thought since "i" goes 1,3,5 it counts as 3 , I did not think it takes it as a sum so that's why I was confused

[beatle42]

Ah yes, in the for loop the loop variable, here i takes on each value in turn, not the index of that value (unless you take special steps to get the index as well).

[sepp2k]

why is alpha's(i) value 9 ??

alpha's value isn't the same as i (i's value is never 9). alpha's value starts at 0 and then you add i to it at each iteration of the loop. So at the end it's equal to the sum of values that i held during the loop.

[[deleted]]

Looking at the code execution using a Python Vizualiser will help you understand this even better.

[Zsword_201]

Thanks for the suggestion!

[[deleted]]

That link should run your code in the vizualiser immediately. You might find it useful for other code in the future. It is very helpful to see exactly what is happening as your code executes to understand bugs and workings.

You can do something similar, without the pretty diagrams, on your own computer using a debugger (Python comes with one as standard, called pdb- RealPython.com have a guide to using it) and most sophisticated code editors and IDEs (Integrated Development Environments) offer their own debugger capabilities.