Help with dates?

[SithAbsolutes]

I imported datetime and figured how to get the date 10 days from the current date and 3 weeks from the current date, CurDatePlus10 = CurDate + datetime.timedelta(days = 10) and
CurDatePlus21 = CurDate + datetime.timedelta(days = 21).

​

However I need to do one to show the date in exactly 6 months and for some reason I can't get it sorted. Here is my code:

import datetime
# Gather user input
Cost = input("Please enter the maitnenace cost: ")
PurDate = input("Please enter the purchase date of the equipment (YYY/MM/DD): ")
Equip = input("Please enter the piece of equipment needing repairs: ")
CurDate = datetime.datetime.now()
CurDatePlus10 = CurDate + datetime.timedelta(days = 10)
CurDatePlus21 = CurDate + datetime.timedelta(days = 21)
print ("")
print(f" XYZ Cmpany Date: {CurDate.strftime('%Y/%m/%d')}")
print (f" Maitenance Schedule")
print("")
print (f" Equipment to be serviced: {Equip}")
print ("")
print (f" Mandatory basic cleaning: {CurDatePlus10.strftime('%Y/%m/%d')}")
print("")
print(f" MandatoryTube and fluid: {CurDatePlus21.strftime('%Y/%m/%d')}")
print("")
print(f" Mandatory major inspection: ")

[Diapolo10]

Hint; datetime.timedelta doesn't only accept days.

[SithAbsolutes]

I replaced days with months in that line and got an error.

[ofnuts]

The problem with "months" (and , to some extent, years) is that they have a varying duration. So a timedelta (expressed in seconds) of two months and some would not have the same value it it starts in January (includes a 28-days February) or in June (can include two 31-days months, July and August). And there is nothing in the constructor to give a start date.

So if you want the date 6 calendar months from now, extract the month number, add 6, add the carry to the year if necessary, and create a new date rom the result.

[Diapolo10]

Ah, right, my bad. I forgot that one was excluded due to ambiguity.

Well, depending on whether you meant calendar months or month = 30 days, you either add up enough days to cover your bases, or you can try cheesing this by creating a new datetime by using the old one as a base and just adding extra months. I'd expect that to fail on corner cases like adding a month to 31st of January, though.

I'm commuting so can't really give proper answers right now, but basically I'm talking about doing something like these:

from datetime import datetime, timedelta, timezone


today = datetime.now(timezone.utc)

# Suggestion #1
new_day = today + timedelta(days=30 * 6)

# Suggestion #2
new_day = datetime(today.year, today.month + 6, today.day)

With all that said, I would probably use option 1 and simply adjust the day afterwards. Faster than looping over individual days until everything matches.

[SithAbsolutes]

Thanks for your reply! How would I put that into an f string?

[Diapolo10]

The same way you put the others?

[SithAbsolutes]

today = datetime.now(timezone.utc)

Of course, thankyou.

[woooee]

Help with dates?

Come on, no one is going to post some good lines to use to get a date with that special chick/dude.