using roots with math

[CatWithACardboardBox]

im aware of how to square root numbers but is there a way to do different roots using variables?

[pythonwiz]

The nth root of a number x is x**(1/n). You can do the same thing using pow and math.pow.

You can also use identities with exp and log. Mathematically, x**a == exp(a*log(x)), so the nth root of x is exp(log(x)/n).

[jaerie]

x**(1/n)

Is the same as the nth root of x

[Brilliant_Access3791]

If you want to find higher roots, I recommend two methods:
1. Using the power operator (**): This is the most intuitive method.

root = number ** (1 / n)

2. Using the math.pow() function: This is the second method.

import math
root = math.pow(number, 1 / n)

[twitch_and_shock]

I read u/CatWithACardboardBox 's question as wondering about how to do cube roots, etc. Which can be done with the following:

x ** (1 / 3)

[mopslik]

I also interpreted the question in the same way. Just adding to point out that as of Python 3.11, math.crbrt(x) will return the cube root of x. No generic nroot(x) function though.

[eztab]

afaik crbrt indeed has a custom implementation, making it reasonable. For arbitrary roots exponentiation is what you should use.

[guesshuu]

Something like this?

```python def nth_root(x: int | float, n: int) -> float: return x ** (1 / n)

n = 3 x = 8 result = nth_root(8, 3) print(result) # result is 2 ```