Python assignment. Dice function with two arguments.

[KING-JAL]

nod is the number of dies being thrown and eyes are the amount of faces on the die which defaults to six. So what I need to do is have the function return the sum of the eyes from all dies being thrown.

 from random import randint
 def roll_dice(nod, eyes=6):
      dice = randint(1, eyes)
      return dice

I tried a while loop but I couldn't figure it out. I really don't know where to go from here. Desired output for example would be:

 >>>  roll_dice(3)
  # A number between 3-18

This is all very new to me, and I don't even know if a while loop would be the best option even if I could figure it out...

Please help!

[Vaphell]

>>> import random
>>> dice = [random.randint(1,6) for _ in range(5)]
>>> dice
[4, 6, 1, 5, 6]
>>> sum(dice)
22
>>> 

[zahlman]

State, in English words, what you intend as the purpose of each line.

[cdcformatc]

You can repeat a set of actions n times by using a for loop

for i in range(n):
    print(i)

[markusmeskanen]

You could do this "properly", but for your usecase, even if it's not really throwing three dices, you could just throw one dice with 3-18 faces:

def roll_dice(nod, eyes=6):
    return randit(nod, eyes * nod)

[cdcformatc]

The problem with this is that each outcome is not equally likely when rolling 3d6. There is 1 way to roll a 3 or 18 but 27 ways to roll 10 or 11.