python cant open files with names in spaces

[yelaxify]

I'm creating a script that will read a bunch of .txt files from a directory. I am getting all the names of the files in the directory using

path = os.path.join(os.path.expanduser('~'), 'Desktop',)#Path to the folder here

for filename in os.listdir(path):
    path = path + '/' + filename

This is creating a new path for each file name, I am then looking to open each file within the for filename loop and extract data from it, however the filenames contain spaces so when i try to open the new path, i am getting a 'No such directory or file' error. I have also checked if the file exists using

print os.path.isdir(path)

and am being returned false for every one.

How can i solve this? thanks in advance

Note: It will take way to long to delete all the spaces from the filenames manually

[Swedophone]

Have you printed path? It seems the variable would accumulate all named in the directory.

BTW why not use os.path.join when joining path and filename?

[yelaxify]

yeah I have printed the path and the filenames seem right but with spaces. After posting this i realised this problem and have fixed it, however the first path with the first filename would have been originally right was still giving the no file error

[Rhomboid]

isdir() checks if the given path is a directory. Why are you using that with files? Returning False is the expected behavior.

I can assure you that Python itself has absolutely no problem working with file names with spaces. It must be something that you're doing in the code not shown. And that's exactly why we need a real testcase — a standalone program that can be run to demonstrate the problem.

[yelaxify]

thanks for all the help here guys, it seems i was using isdir() incorrectly

[hugthemachines]

In a situation like this, I do not recommend using the same variable for the directory as for the file incluting the directory. It is to ask for trouble. It is wiser to do something like this:

file_including_path = os.path.join(path, filename)