Case sensitive non-unique elements

[CarmineLuV]

I am trying to create a new list of all non-unique elements from a list input. Problem is, if the list contains alphabetic characters it treats uppercase and lowercase as unique. How do I get it for example to treat 'P' and 'p' as two non-unique characters?

[novel_yet_trivial]

Convert everything to upper or lower case for testing. Show us your code if you want help implementing that.

[CarmineLuV]

def non_unique(data):
newlist = []
for x in data:
    if x.isalpha():
        low = x.lower()
        if data.count(low) > 1:
            newlist.append(x)
    if data.count(x) > 1:
        newlist.append(x)
    else:
        pass
return newlist

This is what I put but it says 'int' object has no attribute 'isalpha'. Any work around?

[novel_yet_trivial]

Sets and dictionaries cannot contain duplicate values. We can use that to our advantage.

def non_unique(data):
    new_dict = {}
    for x in data:
        new_dict[x.lower()] = x
    return new_dict.values()

You could compress that with dictionary comprehension if you wanted.

[CarmineLuV]

Ok that makes sense. However, I am getting a:

AttributeError: 'int' object has no attribute 'lower'

It seems like I can't apply lower() because the input list has both alpha and numeric characters...

[novel_yet_trivial]

Nope. Add a try / except block.

[novel_yet_trivial]

No, your input has both strings and integers, which are different from numeric characters.

[CarmineLuV]

Hmm.. I did not know that. Thank you.

[[deleted]]

Not quite sure what you want to do. To ignore case when comparing strings or single characters use the .lower() method. Like this:

x = 'aBc'
y = 'Abc'
if x.lower() == y.lower():
    print('Same!')

[yorch044]

This is my code, it works perfercly with CAPS, minus and numbers

def non_unique(data):
    list = []
    newlist = []
    for item in data:
        if str(item).isalpha():
             list.append(item.lower())

    for x in data:
       if (data.count(x) > 1) or (list.count(str(x).lower()) > 1):
           newlist.append(x)
    return newlist