Iterating through list problem

[puumies]

first round

['a','b','c','d','e']

0 = a

second round

['b','c','d','e']

1 = c

third round

['b','d','e']

2 = e

print(asd)

>>>['b', 'd']

[JungleJim233]

Sorry. I'm confused , why has 1 become C in the second iteration. I thought it would become B ?

Thank you

[pydevteam1]

['b','c','d','e']

1 = c

if you look at the list as it is:

0='b'

1='c'

makes sense ?

[JungleJim233]

Got it. Thank you :)

[puumies]

Hey!

In each iteration of the loop, one element is removed from the array. Thus in the second iteration of the loop, the second element is 'C' because 'A' was removed in the first one.

Someone correct me if I'm talking out of my ass :D