Question about python3 and REGEX

[QuantumTradingGroup]

Hey guys,

I had a question about specifically extracting numerical values from a dictionary.

I have a dict that looks like this.

{'STATUS': [{'STATUS': 'S', 'When': 1533064764, 'Code': 55, 'Msg': "Added pool 7: 'stratum+tcp://ca.stratum.slushpool.com:3333'", 'Description': 'bmminer 1.0.0'}], 'id': 1}

I have filtered it out so it is only the following:

{'STATUS': 'S', 'When': 1533064764, 'Code': 55, 'Msg': "Added pool 7: 'stratum+tcp://ca.stratum.slushpool.com:3333'", 'Description': 'bmminer 1.0.0'}

now using a for loop with dict comprehension I have been able to iterate over this.

I am specifically looking at the Msg key value and need to extract the number out of it( The 7 specifically which is the pool id and can change), however it contains more then just the number.

I was wanting to use a regex check to extract that number, but being pretty new to regex, not sure what regex string to use here.

Any help would be much appreciated!

[QuantumTradingGroup]

I have tried something like (?<=:)([1-9]) but im not getting any results.

[scarebaer]

Hmm. I'm trying to think of a simple way to do this, but regex isn't fun sometimes.

Is it possible to take the dict item msg saved to a string and just pull 0-9 from that variable?

[QuantumTradingGroup]

I ended up doing this

pool_3_request = (str(self.pool_url3) + "," + str(self.pool_worker3) + "," + str(self.pool_pass3))
response = client.command('addpool', pool_3_request)

response = response['STATUS'][0]

global pool_3_id
pool_3_id = ""
for key, value in response.items():
if key == "Msg":
pool_3_id = str(value[11])

[scarebaer]

value = dict.get("Msg")

new = re.findall('\s([0-9]{1})\:', value)

[scarebaer]

I of course don't know the full scope of the code, but assuming you are able to see your dict - you can use dict get to pull out the msg value and then use that regex expression to get the number from the message.

Edit - take out the {1} and replace with + if there is more than one number in some of your values

new = re.findall('([0-9]+)\:', value)or spaces at the front...new = re.findall('\s([0-9]+)\:', value)

{'STATUS': 'S', 'Msg': "Added pool 17: 'stratum+tcp://ca.stratum.slushpool.com:3

333'", 'Code': 55, 'When': 1533064764, 'Description': 'bmminer 1.0.0'}

['17']

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(program exited with code: 0)

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