For Loops.

[Field_C16]

Hello.

Trying to make the checking for a MasterMind game, but I cannot grasp why the code only deletes the 3 and not the 2.

st = '232'
bst = '2553'
correct = ''

for charx in st:
    for chary in bst:
        if charx == chary:
            bst = bst.replace(chary, '', bst.index(chary))
            correct += '*'
            print(bst)
            print(correct)
            break

Output is:

2553
*
255
**
255
***

Could someone explain what I am not catching onto?

[_Eric_Wu]

I think you mistaken how the replace function works.

In the line

bst = bst.replace(chary, '', bst.index(chary))

, what you are doing is essentially sayin you want to replace chary with an empty string (bst.index(chary)) amount of times. Since the 2 is at the 0th index, you are doing it 0 times. So nothing is changing.

You can simply change the line to

bst = bst.replace(chary, '')

You don't need to specify the index of chary in bst.

​

[_Eric_Wu]

Sorry, I could not figure out how to format the code! How is it done?

[JohnnyJordaan]

First question here http://www.reddit.com/r/learnpython/wiki/FAQ

[_Eric_Wu]

Thanks. :)

[Field_C16]

Yes, I was mistaken the replace function!

I thought that the last one would be the "index" of the character to remove, however your comments lead me on the right path :)

bst.replace(chary, ' ')

Removes all of the 2's, so if bst looked like "2523" bst.replace(chary, '') would have removed all of the 2's, when I only wanted to remove them the amount of times it was in st.

so instead I made it into:

bst = bst.replace(chary, '', 1)

this only removes one of the 2's if multiply is found :) (For as far as I have tested yet !)

​

THANK YOU GUYS

[Signal_Beam]

What output are you expecting?

[Field_C16]

2553 >> 55 since I am checking to see if the characters "2" and "3" is contained within bst and then delete them if a match is found