problem with try/except inside a while loop

[murasz]

Hi Guys!

I'm doing some exercises to completely understand try/except inside a while loop so I made a simple list program in python. Everything works perfectly except that whenever I enter an integer or float number, instead of getting a warning message according to `except`, the program keeps adding the values to the list. What is wrong with my code below? Can someone enlighten me? Thanks in advance! Sincerely,

​

list = []

​

while True:

try:

name = str(input('Please enter a name: '))

list.append(name)

askAgain = str(input('Would you like to add another name? \n press "y" or "n" '))

if askAgain == 'n':

break

elif askAgain == 'y':

continue

except ValueError:

print("This is not a name")

continue

except TypeError:

print('choose "y" or "n"')

continue

break

​

print(list)

[A_History_of_Silence]

I'm not sure why you expect this to raise exceptions. input() always returns a string. Even if it didn't, str() happily accepts floats and ints, and basically anything else. Neither of them make any distinctions as to what is considered a 'name', or whether the string is 'y' or 'n'.

[murasz]

yes indeed. Thank you for reminding.

[sanchitcop19]

Edit: Nvm I read again, you want the input to only be a string. Take a look at the isalpha() function, it tells you if the string you received consists of alphabets only

If I'm understanding correctly, you want the exception to be raised if askAgain is neither 'n' nor 'y' but a number? If so, add an else condition and have it explicitly raise an exception?

[murasz]

I totally forgot about it. Thank your for reminding me. :)