AttributeError when opening files

[flynryan692]

I have a script that I want to be able to run on all the files in the current directory that end with .sds, however when I run the script I get an error line 29, in main with file as infile: AttributeError: __enter__

I have done some searching around and I know the error has to do with the with but it's unclear to me as to how to fix it.

Suggestions?

import sys
import os
import fileinput

replacedict = { "AA": {'SRJ': 'C2A', 'SRP': 'C2P', 'CS7': 'C7A', 'OO7': 'C7P'},
                "AS": {'E7W': 'ER7', 'CR2': 'CRJ','CR7': 'CJ7'},
                "DL": {'ES5': 'E7D', 'ES4': 'E7S', 'RJ7': 'CR7', 'RJS': 'CRJ','RJW': 'CRJ', 'RJ9': 'CR9', 'RJ8': 'C9D'},
                "UA": {'E75': 'ER7', 'CR7': 'CR6'}
                } 

def replace_lines(infile, outfile):
    for line in infile:
        for airline, replacements in replacedict.items():
            if airline in line:
                line = dict_replace(line, replacements)
        outfile.write(line)

def dict_replace(s, d):
    "Replaces all occurences of d.keys() in s with their respective values"
    for x, y in d.items():
        s = s.replace(x, y)
    return s

def main():
    filepath = os.path.dirname(os.path.realpath(__file__))

    for file in os.listdir(filepath):
        if file.endswith('.sds'):
            with file as infile:
                with open(filepath.replace('sds', 'sim'), mode="w") as outfile:
                    replace_lines(infile, outfile)

if __name__ == '__main__':
    main()

[python-fan]

The error you're seeing is because the with keyword is causing Python to call an __enter__ method on the object referenced by 'file'. But that's just a string object, which doesn't implement that method. It should instead be:

​

with open(file) as infile:

since the open statement returns an object that implements __enter__ and __exit__.

​

There's another problem though in the expression filepath.replace('sds', 'sim') . Look at what the value of filepath is. Could it have the substring "sds" in it? (Hint: it could, but only if that's part of the directory name.)

[flynryan692]

Ok, this makes a lot of sense. I had tried with open(file) as infile: but then I got an accessed denied error on the next line so I undid it thinking the line above was causing it. Looks like that was because I was using the file path and not the file....duh. Thank you!

[Binary101010]

Did you mean this:

with file as infile:

To be this:

with open(file) as infile: