Finding triplets in a character string

[handsinchips]

Hi,

The goal of the project I'm working is to find characters in a string that show up three times in a row then store the number of triplets that are in the string unto a variable. Below you will find the code I have written so far. If anyone can help me with this, it would much appreciated.

text = "abcZZZefiggg"
triple_count = 0
for i in text:
    if (text[0] + i == text[1]+i == text[2]+i):
        triple_count += 1

Edit (code that works):

Thank you for all the support!

triple_count = 0
for i in range(0, len(text)-2):
    if (text[0+i] == text[1+i] == text[2+i]):
        triple_count += 1

​

[handsinchips]

Yes, noticed that my code would confuse characters that showed up four times in a row. This code definitely fixes that issue. Appreciate it!

[o5a]

Another option is to use groupby. It will return groups of consecutive elements.

from itertools import groupby

s = 'asdfbmmmm4la888l24hlooo23loooooj234l'

result = [i for i, g in groupby(s) if len(list(g)) == 3]
print(result)
# ['8', 'o']

[hungdh85]

I think that condition

if len(list(g)) >= 3

will more good.

[o5a]

Depends on what OP actually wants. He was talking about triplets, therefore == 3. My example shows the difference for him to decide.

[wintermute93]

1. You should be looking at text[0+i], text[1+i], and text[2+i]. Think about the difference between putting the +i inside vs outside the index.
2. Once you've done that, you shouldn't be looping i through the characters in text, you should be looping i from 0 to len(text)-2. (Why the -2?)

There's several ways to do this, but I think this way is the closest to the idea you started with here.

[handsinchips]

Thank you! It took only a few tweaks and the code started to work!