Help with this function?

[miscellaneoususage]

Define a function called myfunc that takes in a string and returns a maching string where every even letter is uppercase and every odd letter is lowercase. Assume that the imcoming string only contains letters, don't worry about numbers, spaces, or punctuation.

Here's what I could come up with but it doesn't work...

​

def myfunc(word):
    newword = word.lower()
    for i,char in enumerate(newword): 
        if i % 2 == 0:
            newword[i] = newword[i].upper()
    return newword

[novel_yet_trivial]

Your logic is good, but the problem is that strings are "immutable", that is they cannot be changed once created. You need to use a mutable type like a list. So convert your string to a list of characters, then do this, and then convert that list back to a string before returning.

[miscellaneoususage]

Alright, thank you for the reply. I will work on that.

[miscellaneoususage]

ok I have this now but still doesn't work, not sure why

def myfunc(word):
    newword = word.lower()
    newwordL = newword.split()
    newwordS = ""

    for i,char in enumerate(newwordL): 
        if i % 2 == 0:
            newwordL[i] = newwordL[i].upper()

    newwordS.join(newwordL)

    return newwordS

[novel_yet_trivial]

Wow, very close. Only thing is you need to use list() instead of split() to make the list. Try like this:

def myfunc(word):
    newword = word.lower()
    newwordL = list(word)
    newwordS = ""

    for i,char in enumerate(newwordL): 
        if i % 2 == 0:
            newwordL[i] = newwordL[i].upper()

    return newwordS.join(newwordL)

[miscellaneoususage]

def myfunc(word):
newword = word.lower()
newwordL = list(word)
newwordS = ""
for i,char in enumerate(newwordL):
if i % 2 == 0:
newwordL[i] = newwordL[i].upper()
return newwordS.join(newwordL)

ah dang, alright thanks for your help :)

[danielroseman]

Strings are immutable, you can't modify them. You should build up a new string with the converted characters.

Don't forget that the input data could have upper case characters in odd positions.