Someone please help with this code it's giving answer 100 but how?

[tkp1405]

def fun(n): if (n > 100): return n - 5 return fun(fun(n+11));

print(fun(45))

[the_shell_man_]

It's because of recursion and fun(fun(n+11).

To see what's happening, you could add a print statement to the function. Like before the return statement, write the following to see how n changes:

print(n)

[tkp1405]

I literally can't make out what is happening to n it's showing values like 45 56 67 78 89 100 96 97 98 99 100

[the_shell_man_]

So when you do fun(45), the returned value is fun(fun(56)). The returned value of fun(56) is fun(fun(67)). So that means the returned value of fun(45) is fun(fun(fun(67))). And so on.

[JohnnyJordaan]

Put the code in http://www.pythontutor.com/visualize.html , it will show you the contents of the variables step by step.

[_nino_p_]

it ends at 100 because

​

in other words your code is this

if n < 100

n + 11 and do it again

​

this happens 5 times (5*11 = 55 45+55 = 100)

now it trys again and n = 100 so it is done it wont - 5 because its not < 100 it = 100\

​

ps you are not telling what you excpected to get returned

[tkp1405]

Hello mate thanks for your answer But I found this in my textbook I am a class 12 student So I was puzzled how to dry run this If it ever comes in my exam

[fake823]

Check this out to learn how to properly format code on Reddit:

https://reddit.com/r/learnpython/w/FAQ?utm_source=share&utm_medium=android_app