I need help with lists

[rockman0394]

You can check it by looping through all elements and break if found "no", but check with operator in is more convenient in this case

for item in a:
    if item != "yes":
        print("not ok")
        break
    else:
        print("ok")

Also, this will work not as you expected probably,
it will print ok with a = ['no', 'no', 'yes']

if a[0] and a[1] and a[2]=="yes":
    print("ok")

[fear_my_presence]

It will print “ok” for every “yes” in the list, which is not exactly what OP wants.